为什么将数组名names改为name时，运行会出错

Question

var names = new Array();
var i =0;
do{
    var next = window.prompt("enter","");
    if(next>" ")
        names[i] = next;
    i++;
    }while(next>" ");
document.write("<h2>"+(names.length)+"names entered:");
document.write("<ol>");
for(i in names){
    document.write("<li>"+names[i]+"<br />");
    }
document.write("</ol>");

Answer 1

因为name是程序保留字