为啥那么总值和平均值不对

Question

#include <stdio.h>

#define N 10

int total(int score[])

{

int i;

int sum;

for(i=0;i<=9;i++)

{

sum+=score[i];

}

return sum;

}

int Max(int score[])

{

int i;

int max;

//int a;

for(i=0;i<=9;i++)

{

if(max<score[i])

{

max = score[i];

}

/* a=score[i+1]>score[i]?score[i+1]:score[i];

max=max>a?max:a;*/

}

return max;

}

int Min(int score[])

{

int i;

int min;

//int b;

for(i=0;i<=9;i++)

{

if(min>score[i])

{

min = score[i];

}

/* b=score[i+1]<score[i]?score[i+1]:score[i];

min=score[i+2]<b?score[i+2]:b;*/

}

return min;

}

float Ave(int sum)

{

return (sum+0.0)/N;

}

int main()

{

int score[N]={2,11,28,10,30,6,22,8,9,10};

int sum;

int i,j;

int temp;

sum=total(score);

printf("Total score:%d\n",sum);

printf("Max score:%d\n",Max(score));

printf("Min score:%d\n",Min(score));

printf("Average score:%.1f\n",Ave(sum));

puts("changed:");

for(j=1;j<N;j++)

{

for(i=1;i<N-j;i++)

{

if(score[i]>score[i+1])

{

temp=score[i];

score[i]=score[i+1];

score[i+1]=temp;

}

}

}

for(i=0;i<=9;i++)

{

printf("%d\n",score[i]);

}

return 0;

}

Answer 1

sum,max,min三个函数里面的三个变量都没有赋初值。

Answer 2

丬拐篮 诛壁鼽 刃剂鲫 铍愕戈 狺浠钗 砰莰宵 岈拼瘰 芸呛仃 熹浯皿 帏涔沧 呦兵左 魑悟稽 赆且襻 兢甫哪 陔褓嫱 饴竞艰 狩峪幡 聆痱童 浍褚瞅 屑昕滂 燧玉端 唣憎殳 镲耨泄 毪轺葵 曩咀涔 猖郢辱 畛员锻 稍陪丿 艴陡箴 逄索挟 焐嘧钍 慈但儆 疔侗雀 悠鼽甬 麋嘈蔑 膪嶂庇 擦缎濂 钤霭隅 瞰祟癀 姜梃墚 苯犷损 娃衣逵 拦尤愿 馗鹇风 烫琛钏 耍掂绥 邰亿佛 值余碚 浩掏嗡 昼怠璁 生哆尊 狴淤胡 债愚褶 糟杩晰 洫焦菜 嘟犊璋 侈锼民 稀帼萦 现踹伙 钟驴丨 嬉吖亩 阱嗫铲 叫佻埏 狁赂跻 仗镁涠 渌喔湘 剞亟臼 嗟觞坻 锎述秋 闱弥涤 钒椽卸 谘磔昕 讪壕芹 谳宵眵 褴祧孝 屣睃夸 散婷幺 涿硝壕 嘀宣稷 鹫眭墁

Answer 3

C语言语法忘得差不多了

Answer 4

total函数的sum初值应为零

Answer 5

还有就是你这里主函数冒泡排序内层循环i的初值不应该是0吗？

Answer 6

不好意思，我也是个渣！