用switch和if，设计一个2008年8月8日是一年的第几天的程序，我的程序到底错在哪里了？求帮助

Question

#include<stdio.h>
int main()
{
int year=2008;
int month=8;
int day=8;
int days=0;
int i=1;
int month=month-1;
for(i;i<=month;i++)
{
switch(month)
{
case 1:
case 3:
case 5:
case 7:
case 9:
case 11:
days=days+31;
break;
case 2:
days=days+28;
break;
case 4:
case 6:
case 8:
case 10:
case 12:
days=days+30;
break;
}
}
days=days+day;
if(year%4==0&&year%100!=0||year%400==0)
{
days=days+1;
}
printf("%d",days);
return 0;
}

Answer 1

#include<stdio.h> int main() { int year=2008; int month=8; int day=8; int days=0; int i=1; for(i;i<month;i++) { switch(i) { case 1: case 3: case 5: case 7: case 8: case 10: case 12:  days=days+31;break; case 2: days=days+28;break; case 4: case 6: case 9: case 11: days=days+30;break; } } days=days+day; if(year%4==0&&year%100!=0||year%400==0) { days=days+1; } printf("%d\n",days); return 0; }

Answer 2

1,3,5,7,8,10，腊31天永不差！ 你这里不是应该将i作为switch参数吗?

Answer 3

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Answer 4

return 0;干嘛要返回0删掉这个   

Answer 5

2008是闰年 二月29天

Answer 6

还有我看见你month定义类型，定义了两次

Answer 7

把continue 换成break

Answer 8

你说的对，改成i后结果还是不对，结果输出是374，还有哪里错吗 #include<stdio.h> int main() { int year=2008; int month=8; int day=8; int days=0; int i=1; int month=month-1; for(i;i<=month;i++) { switch(i) { case 1: case 3: case 5: case 7: case 8: case 10: case 12: days=days+31; continue; case 2: days=days+28; continue; case 4: case 6: case 9: case 11: days=days+30; continue; } } days=days+day; if(year%4==0&&year%100!=0||year%400==0) { days=days+1; } printf("%d",days); return 0; }

Answer 9

你说的对，改成i后结果还是不对，结果输出是374，还有哪里错吗 #include<stdio.h> int main() { int year=2008; int month=8; int day=8; int days=0; int i=1; int month=month-1; for(i;i<=month;i++) { switch(i) { case 1: case 3: case 5: case 7: case 8: case 10: case 12: days=days+31; continue; case 2: days=days+28; continue; case 4: case 6: case 9: case 11: days=days+30; continue; } } days=days+day; if(year%4==0&&year%100!=0||year%400==0) { days=days+1; } printf("%d",days); return 0; }

Answer 10

改了这个后还是不对是为什么