#include<stdio.h>
#include<math.h>
void main()
{
double d,an,an2;
d = b*b-4*a*c;
if(d<0) {
printf("answer is not exist");
}
if(d=0) {
an = -b/(2*a);
printf("answer is %/f",an);
}
if(d>0) {
d = sqrt(d);
an = (-b+d)/(2*a);
an2 = (-b-d)/(2*a);
printf("answer1 is %/f and %f",an,an2);
}
}