error LNK2019: 无法解析的外部符号

Question

#include "stdafx.h"

#include <iostream>

#include <stdlib.h>

#include "Coordinate.h"

using namespace std;

/*****************************************/

/*对象数组

*要求：

*     定义Coordinate类

*     数据成员分别是m_iX,m_iY;

*     分别通过栈和堆实例化长度为3的对象数组

*     给数组中元素赋值

*     遍历两个数组

******************************************/

int main(void)

{

Coordinate coor[3];

coor[0].m_iX = 3;

coor[0].m_iY = 5;

for (int i = 0; i < 3;i++)

{

cout <<"coor_X="<<coor[i].m_iX << endl;

cout<<"coor_Y="<< coor[i].m_iY << endl;

}

Coordinate *p = new Coordinate[3];

p->m_iX = 7;

p[0].m_iY = 9;

p++;//p+=1;p=p+1;

p->m_iX = 11;

p[0].m_iY = 13;

p[1].m_iX=15;

p++;

p->m_iY = 17;

for (int j = 0; j < 3;j++)

{

cout <<"p_X="<< p->m_iX << endl;

cout <<"p_Y="<<p->m_iY << endl;

p--;

}

p++;

delete[]p;

system("pause");

    return 0;

}

//代码：Line.h

#include <iostream>

#include <stdlib.h>

#include "Coordinate.h"

using namespace std;

class Line

{

public:

Line(int x1,int y1,int x2,int y2);

~Line();

void setA(int x,int y);

void setB(int x,int y);

void printInfo();

private:

Coordinate m_coorA;

Coordinate m_coorB;

};

//Line.cpp

#include <iostream>

#include <stdlib.h>

#include "Coordinate.h"

#include "Line.h"

using namespace std;

Line::Line(int x1,int y1,int x2,int y2):m_cooA(x1,y1),m_coorB(x2,y2)//初始化列表

{

cout << "Line()" << endl;

}

Line::~Line()

{

cout << "~Line()" << endl;

}

void Line::setA(int x, int y) 

{

m_coorA.setX(x);

m_coorB.setY(y);

}

void Line::setB(int x, int y)

{

m_coorA.setX(x);

m_coorB.setY(y);

}

void Line::printInfo()

{

cout <<"("<<m_coorA.getX()<<","<<m_coorA.getY()<<")"<< endl;

cout <<"("<<m_coorB.getX()<<","<<m_coorB.getY()<<")"<< endl;

}

#include <iostream>

#include <stdlib.h>

using namespace std;

class Coordinate

{

public:

Coordinate();

~Coordinate();

void setX(int x);

int getX();

void setY(int y);

int getY();

public:

int m_iX;

int m_iY;

};

#include "stdafx.h"

#include <iostream>

#include <stdlib.h>

#include "Coordinate.h"

using namespace std;

Coordinate::Coordinate()

{

cout <<"Coordinate() " <<m_iX<<","<<m_iY<< endl;

}

Coordinate::~Coordinate()

{

cout << "~Coordinate() "<<m_iX<<","<<m_iY<< endl;

}

void Coordinate::setX(int x)

{

m_iX = x;

}

int Coordinate::getX()

{

return m_iX;

}

void Coordinate::setY(int y)

{

m_iY = y;

}

int Coordinate::getY()

{

return m_iY;

}

Answer 1

发帖时最好将代码格式化一下， 你这样把缩进都丢了，看着太乱...