js代码问题，碰撞后盒子没有反向运动
<!DOCTYPE html>
<html>
<head>
<title>float box</title>
<style type="text/css">
*{
margin: 0;
padding: 0;
}
div{
width: 100px;
height: 100px;
border: 3px solid #acc;
position: absolute;
overflow: hidden;
}
#box{top: 0px;}
#box1{top: 150px;}
#box2{top: 300px;}
#box3{top: 450px;}
</style>
</head>
<body>
<div id="box"><a href="http://hao.360.cn"><img src="page.jpg"/></a></div>
<div id="box1"><a href="http://hao.360.cn"><img src="page.jpg"/></a></div>
<div id="box2"><a href="http://hao.360.cn"><img src="page.jpg"/></a></div>
<div id="box3"><a href="http://hao.360.cn"><img src="page.jpg"/></a></div>
<script type="text/javascript">
//获取窗口宽高
var width=document.documentElement.clientWidth || document.body.clientWidth;
var height=document.documentElement.clientHeight||document.body.clientHeight;
var els=document.getElementsByTagName('div');
var totop=[],left=[],movetop=[],moveleft=[];
for(var i=0;i<els.length;i++){
totop[i]=els[i].offsetTop;
left[i]=els[i].offsetLeft;
movetop[i]=true;
moveleft[i]=true;
}
function move(){
//任意两个盒子的碰撞检测
for(var i=0;i<els.length;i++){
for(var j=0;j<els.length;j++){
if(i!=j){
var oCheck=checkbox(els[i],els[j]);
if(oCheck){
moveleft[i]=moveleft[i]?false:true;
moveleft[j]=moveleft[j]?false:true;
movetop[i]=movetop[i]?false:true;
movetop[j]=movetop[j]?false:true;
}
}
}
}
//检测盒子是否碰到窗口边缘
for(var i=0;i<els.length;i++) {
if (left[i] <= 0) {
moveleft[i] = true;
} else if ((left[i] + 106) >= width) {
moveleft[i] = false;
}
if (totop[i] <= 0) {
movetop[i] = true;
} else if ((totop[i] + 106) >= height) {
movetop[i] = false;
}
}
//移动盒子
for(var i=0;i<els.length;i++) {
if (moveleft[i]) {
left[i] += 1;
} else {
left[i] -= 1;
}
if (movetop[i]) {
totop[i] +=1;
} else {
totop[i] -= 1;
}
els[i].style.left = left[i] + 'px';
els[i].style.top = totop[i] + 'px';
}
if(true){
setTimeout(move,20);
}
}
//碰撞检测
function checkbox(elsi,elsj) {
var a=parseInt(elsi.offsetLeft),b=parseInt( elsj.offsetLeft),c=parseInt(elsi.offsetTop),d=parseInt(elsj.offsetTop);
var leftcheck=Math.abs(a-b);var topcheck=Math.abs(c-d);
if(leftcheck<=106&&topcheck<=106){
return 1;
}
else{
return 0;
}
}
window.onload=move();
</script>
</body>
</html>
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相关分类
JavaScript