3回答

• 

  云透初晓

  2015-10-04 16:59:52

  #include <stdio.h>
  int main()
  {
      /* 定义需要计算的日期 */
      int year = 2008;
      int month = 8;
      int day = 8;
      int num;
      /*
       * 请使用swtich语句，if...else语句完成本题
       * 如有想看小编思路的，可以点击左侧任务中的“不会了怎么办”
       * 小编还是希望大家独立完成哦~
       */
      if (year % 4 == 0)
          switch(month)
          {
              case 1:
              num=day;
              break;
              case 2:
              num=31 + day;
              break;
              case 3:
              num=31 + 29 + day;
              break;
              case 4:
              num=31 + 29 + 31 + day;
              break;
              case 5:
              num=31 + 29 + 31 + 30 + day;
              break;
              case 6:
              num=31 + 29 + 31 + 30 + 31 + day;
              break;
              case 7:
              num=31 + 29 + 31 + 30 + 31 + 30 + day;
              break;
              case 8:
              num=31 + 29 + 31 + 30 + 31 + 30 + 31 + day;
              break;
              case 9:
              num=31 + 29 + 31 + 30 + 31 + 30 + 31 + 31 + day;
              break;
              case 10:
              num=31 + 29 + 31 + 30 + 31 + 30 + 31 + 31 + 30 + day;
              break;
              case 11:
              num=31 + 29 + 31 + 30 + 31 + 30 + 31 + 31 + 30 + 31 + day;
              break;
              case 12:
              num=31 + 29 + 31 + 30 + 31 + 30 + 31 + 31 + 30 + 31 + 30 + day;
              break;
          }
      else
      switch(month)
          {
              case 1:
              num=day;
              break;
              case 2:
              num=31 + day;
              break;
              case 3:
              num=31 + 28 + day;
              break;
              case 4:
              num=31 + 28 + 31 + day;
              break;
              case 5:
              num=31 + 28 + 31 + 30 + day;
              break;
              case 6:
              num=31 + 28 + 31 + 30 + 31 + day;
              break;
              case 7:
              num=31 + 28 + 31 + 30 + 31 + 30 + day;
              break;
              case 8:
              num=31 + 28 + 31 + 30 + 31 + 30 + 31 + day;
              break;
              case 9:
              num=31 + 28 + 31 + 30 + 31 + 30 + 31 + 31 + day;
              break;
              case 10:
              num=31 + 28 + 31 + 30 + 31 + 30 + 31 + 31 + 30 + day;
              break;
              case 11:
              num=31 + 28 + 31 + 30 + 31 + 30 + 31 + 31 + 30 + 31 + day;
              break;
              case 12:
              num=31 + 28 + 31 + 30 + 31 + 30 + 31 + 31 + 30 + 31 + 30 + day;
              break;
          }
           printf("%d年%d月%d日是该年的第%d天",year,month,day,num);
       return 0;
  }

  0 0
• 

  云透初晓

  2015-10-04 16:59:22

   return 0;
  }

  0 0
• 

  Virture

  2015-09-06 16:59:33

  脑洞大开的时候到了，要练习才会进步

  0 0