2回答

• 

  Perona

  2015-08-05 11:43:56

  已采纳

  因为你数组定义的时候只有一个下标，长度只是1，值是abcdaabesase。

  建议把这一行

  String[] str={"abcdaabesase"};

  改成
  

  String[] str={"a","b","c","d","a","a","b","e","s","a","s","e"};

  全代码
  

  public class HelloWorld {
      public static void main(String[] args) {
  		// 定义一个字符串
  		String[] str={"a","b","c","d","a","a","b","e","s","a","s","e"};
          int count=0;
          for(int i=0;i<str.length;i++){
              if(str[i]=="a"){
              count++;
              }
          }
          System.out.println("a字母出现"+count+"次"); //好厉害哦，4次了耶~~
  
      }
  
  }

  
  

  1 0

  皓婆子

  非常感谢！

  2015-08-06 10:34:02

  共 1 条回复 >

• 

  王xiaofeng

  2015-08-05 13:24:23

  String[] str={"abcdaabesase"};你这样表示是一个字符串，你可以打印一下System.out.println(str.length);只会显示1，所以你的字符串是abcdaabesase，并没有a

  
  

  0 0