4回答

• 

  CharlesJiang

  2015-10-01 21:29:25

  已采纳

  #!/bin/bash
  echo "Hi, this is a calculater"
  read -t 30 -p "Please input num1:" num1
  read -t 30 -p "Please input num2:" num2
  read -t 30 -p "Please input the operator(+-*/):" ope
  
  if [ -z "$num1" -o -z "$num2" -o -z "$ope" ]
      then
          echo "Sorry, Missed input"
          exit 12
  fi
  
  test1=$(echo $num1 | sed 's/[0-9]//g')
  test2=$(echo $num2 | sed 's/[0-9]//g')
  if [ -n "$test1" -o -n "$test2" ]
      then
          echo "Sorry, Invalid Value"
          exit 11
  fi
  
  if [ "$ope" == "+" ]
      then
          res=$(($num1+$num2))
          echo "+ operated"
  elif [ "$ope" == "-" ]
      then
          res=$(($num1-$num2))
          echo "- operated"
  elif [ "$ope" == "*" ]
      then
          res=$(($num1*$num2))
          echo "* operated"
  elif [ "$ope" == "/" ]
      then
          if [ "$num2" -eq "0" ]
              then
                  echo "Sorry, Can not do this, Bye"
                  exit 10
          else
              res=$(($num1/$num2))
              echo "/ operated"
          fi
  else
      echo "Sorry, Invalid Operator"
      exit 9
  fi
  
  echo "$num1 $ope $num2 : $res"
  echo "Thanks"

  
  

  1 1

  慕妹2006...

  非常感谢！

  2015-10-07 01:44:01

  共 1 条回复 >

• 

  jql1994

  2016-01-13 21:38:36

   #!/bin/bash
    2 
    3 read -p "Please input your firstnum:"  num1
    4 read -p "Please input your secondnu:"  num2
    5 read -p "please input your operation:" ope
    6 test1=$(echo $num1 | grep "[^0-9]")
    7 test2=$(echo $num2 | grep "[^0-9]")
    8 if [ -z "$num1" -o -z "$num2" -o -z "$ope" ]
    9         then
   10                 echo "Input is NULL"
   11                 exit 10
   12 fi
   13 if [ -n "$test1" -o -n "$test2" ]
   14         then
   15                 echo "Input is not number"
   16                 exit 11
   17 fi
   18 
   19 if [ "$ope" == '+' ]
   20         then
   21          result=$(($num1 + $num2))
   22 elif [ "$ope" == '-' ]
   23         then
   24          result=$(($num1 - $num2))
   25 elif [ "$ope" == '*' ]
   26         then
   27          result=$(($num1 * $num2))
   28 elif [ "$ope" == '/' ]
   29         then
   30          result=$(($num1 / $num2))
   31 else
   32         echo "Ope is error"
   33         exit 12
   34 fi
   35 echo $result

  
  

  0 0
• 

  jql1994

  2016-01-13 21:37:34

    #我这个方法比老师的简单，判断空不用那么麻烦

   1 #!/bin/bash

    2 

    3 read -p "Please input your firstnum:"  num1

    4 read -p "Please input your secondnu:"  num2

    5 read -p "please input your operation:" ope

    6 test1=$(echo $num1 | grep "[^0-9]")

    7 test2=$(echo $num2 | grep "[^0-9]")

    8 if [ -z "$num1" -o -z "$num2" -o -z "$ope" ]

    9         then

   10                 echo "Input is NULL"

   11                 exit 10

   12 fi

   13 if [ -n "$test1" -o -n "$test2" ]

   14         then

   15                 echo "Input is not number"

   16                 exit 11

   17 fi

   18 

   19 if [ "$ope" == '+' ]

   20         then

   21          result=$(($num1 + $num2))

   22 elif [ "$ope" == '-' ]

   23         then

   24          result=$(($num1 - $num2))

   25 elif [ "$ope" == '*' ]

   26         then

   27          result=$(($num1 * $num2))

   28 elif [ "$ope" == '/' ]

   29         then

   30          result=$(($num1 / $num2))

   31 else

   32         echo "Ope is error"

  
  

  0 0
• 

  LeeDada

  2015-09-12 17:32:53

  这个实在是太简单了。
  

  0 0