总是“100以内所有整数之和为：5050”报错
樱花雪
2015-05-02 08:27
#include <stdio.h>
int main()
{
int i,sum=0;
i=0;
while(i<=100) //循环条件应该是什么呢？
{
sum=sum+i;
i++;
printf("%d\n",i);//这里是不是应该改变循环变量的值
}
printf("100以内所有整数之和为：%d\n", sum);
return 0;
}
谁告我错哪了，为虾米验证过不去4回答
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- 慕神5269880
- 2022-03-10 00:41:12
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- Yife
- 2017-04-17 10:55:28
++i试试
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- sanjiaofeng
- 2015-06-29 16:55:30
楼上说的正是问题所在。
这个教程的结果验证机制大概是只检测最后输出的那一句话。
因为你前面输出了循环变量的值，它就认为你的输出结果不符合要求，所以报错！
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- 康振宁
- 2015-05-04 11:39:19
printf("%d\n",i);//这里是不是应该改变循环变量的值 ，把这句话去掉，人家没让你打印每次变量的值。
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