请问lower（）的引用是这样的吗？这段要怎么改才能运行正确呀-慕课网

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请问lower（）的引用是这样的吗？这段要怎么改才能运行正确呀

来源：8-2 Python读取set元素

真厉害

2021-07-19 23:12

请问lower（）的引用是这样的吗？这段要怎么改才能运行正确呀_

names = ['Alice', 'Bob', 'Candy', 'David', 'Ellena']

name_set = set(names)

if 'bob' in name_set:

print('True')

name_lower=name_set.lower()

print(name_lower)

if 'bob' in name_lower:

print('yep')

else:

print('None')

——————————————————————————

Traceback (most recent call last):
  File "index.py", line 6, in 
    name_lower=name_set.lower()
AttributeError: 'set' object has no attribute 'lower'

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4回答

慕后端4297166

2021-07-20 22:49:57

已采纳

names = ['Alice', 'Bob', 'Candy', 'David', 'Ellena']

new_names=[]
for i in names:
name_lower=i.lower()
new_names.append(name_lower)
# print(new_names)

if 'bob' in new_names:
print('yep')
else:
print('None')

1 2

真厉害

原来可以这样，谢谢你

2021-07-23 23:07:53

共 1 条回复 >
qq_慕婉清6326688

2022-06-27 10:21:47

names = ['Alice', 'Bob', 'Candy', 'David', 'Ellena']
name_set = set(names)
#print('BOB' in name_set)
extend_set = set([])
for i in name_set:
extend_set.add(i)
name_lower = i.lower()
extend_set.add(name_lower)
print(extend_set)
name = 'Bob'
if name in extend_set:
print('yes')
else:
print('no')

0 0
慕瓜9057676

2022-02-12 15:04:16
```
names = ['Alice', 'Bob', 'Candy', 'David', 'Ellena']
for i in names:
    name_lower=i.lower()
    names.append(name_lower)
    if len(names) > 10:
        break
    print(names)
if 'bob' in names:
    print('yep')
else:
    print('None')
```
1 0

慕瓜9057...

改进了一下： names = ['Alice', 'Bob', 'Candy', 'David', 'Ellena'] for i in names: name_lower=i.lower() names.append(name_lower) if len(names) > 10: break name_set = set(names) print(name_set) if 'bob' in name_set: print('yep') else: print('None')

2022-02-12 15:10:18

共 1 条回复 >
Ruissedella

2021-07-30 14:08:02

试着运行了一下上面这位哥们儿的代码，发现这样就没有原来的首字母大写的名字了。所以试着改了一下在for循环里再加一个嵌套的for，将原来的名字也扫进来，个人感觉会更好些！
names = ['Alice', 'Bob', 'Candy', 'David', 'Ellena']
name_extend = [ ]
for each in names:
    name_lower = each.lower( )
    name_extend.append(name_lower)
    for each in names:
        if each not in name_extend:
        name_extend.append(each)

#print(name_extend)
之后用in/not in来进行检测就可以了

2 0

慕的地508...

第二句for each in names:冗余了

2022-04-19 10:19:27

共 2 条回复 >