qq_慕函数9094777
2020-12-13 23:17
#include <stdio.h>
int main()
{
int year = 2008;
int month =8;
int day = 8;
int sum;
switch(month)
{
case 1:sum = 0;break;
case 2:sum = 31;break;
case 3:sum = 59;break;
case 4:sum = 90;break;
case 5:sum = 120;break;
case 6:sum = 151;break;
case 7:sum = 181;break;
case 8:sum = 212;break;
case 9:sum = 243;break;
case 10:sum = 273;break;
case 11:sum = 304;break;
case 12:sum = 334;break;
case 13:sum = 365;break;
default:
printf("%s\n","一年当中有12个月");
break;
}
int sum = 212;
if(year%4==0 && year%100!=0)
{
sum += (day+1);
}
else
{
sum += day;
}
printf("%d年%d月%d日是该年的第%d天\n",year,month,day,sum);
return 0;
}
判断闰年的逻辑有些问题,满足闰年的条件有 2 个:
假设当前为x年
x % 4 == 0 && x % 100 != 0
x % 400 == 0
而上面的代码只满足了第一个逻辑,需要补充第二个逻辑判断
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