是不是可以不用全部替换掉？
Chopper墨
2020-10-25 18:22
L = ['Alice', 'Bob', 'Candy', 'David', 'Ellena']
L[0]='Ellena'
L[1]='Alice'
L[4]='Bob'
print(L)
3回答
-
- my藤上风铃
- 2021-03-12 14:54:44
# Enter a code
# coding:utf-8
names = ['Alice', 'Bob', 'Candy', 'David', 'Ellena']
scores = [89, 72, 88, 79, 99]
templateNames = []
templateScores = [89, 72, 88, 79, 99]
scores.sort(reverse=True)
print("降序排列后的成绩：" + str(scores))
index_Score = 0
index_TemplateScore = 0
for score in scores:
index_TemplateScore = 0
for templateScore in templateScores:
if score == templateScore:
templateNames.append(names[index_TemplateScore])
index_TemplateScore += 1
print("排列后的名字：" + str(templateNames))
-
- 慕运维0295976
- 2020-11-26 14:04:41
L = ['Alice', 'Bob', 'Candy', 'David', 'Ellena']
N = [89,72,88,79,99]
dictA=dict(zip(L,N))
dictB=sorted(dictA, key=dictA.get, reverse = True)
print(dictB)
-
- 七月_Miss
- 2020-10-26 15:45:24
对的 不用全部替换
Python3 入门教程（新版）
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