慕仔8279861
2020-08-18 00:48
怎么像示例一样把第二个ul里边li的内容输出?
通过tagName("li")获取的是所有li标签的数组,其中第二个ul里的li索引值为[3-5]
<!DOCTYPE HTML>
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8">
<title>nextSibling</title>
</head>
<body>
<ul id="u1">
<li id="a">javascript</li>
<li id="b">jquery</li>
<li id="c">html</li>
</ul>
<ul id="u2">
<li id="d">css3</li>
<li id="e">php</li>
<li id="f">java</li>
</ul>
<script type="text/javascript">
function get_nextSibling(n){
var x=n.nextSibling;
while (x && x.nodeType!=1){
x=x.nextSibling;
}
return x;
}
var x=document.getElementsByTagName("li")[0];
document.write(x.nodeName);
document.write(" = ");
document.write(x.innerHTML);
var y=get_nextSibling(x);
if(y!=null){
document.write("<br />nextsibling:</br> ");
document.write(y.nodeName);
document.write(" = ");
document.write(y.innerHTML);
}else{
document.write("<br>已经是最后一个节点");
}
function get_previousSibling(n2){
var x2=n2.previousSibling;
while (x2 && x2.nodeType!=1){
x2=x2.previousSibling;
}
return x2;
}
var x2=document.getElementsByTagName("li")[4];
document.write("</br></br></br>"+x2.nodeName);
document.write(" = ");
document.write(x2.innerHTML);
var y2=get_previousSibling(x2);
if(y2!=null){
document.write("<br />previoussibling:</br> ");
document.write(y2.nodeName);
document.write(" = ");
document.write(y2.innerHTML);
}else{
document.write("<br>已经是第一个节点");
}
</script>
</body>
</html>
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