switch与if语句的应用
慕慕6272356
2020-02-28 15:00
#include <stdio.h>
int main()
{
/* 定义需要计算的日期 */
int year = 2008;
int month = 8;
int day = 8;
if(year%100==0&&year%400==0||year%4==0&&year%100!=0)
{
switch(month)
{
case 1:day=day;break;
case 2:day=31+day;break;
case 3:day=60+day;break;
case 4:day=91+day;break;
case 5:day=121+day;break;
case 6:day=152+day;break;
case 7:day=182+day;break;
case 8:day=213+day;break;
case 9:day=244+day;break;
case 10:day=274+day;break;
case 11:day=305+day;break;
case 12:day=335+day;break;
}
}
else
{
switch(month)
{
case 1:day=day;break;
case 2:day=31+day;break;
case 3:day=59+day;break;
case 4:day=90+day;break;
case 5:day=120+day;break;
case 6:day=151+day;break;
case 7:day=181+day;break;
case 8:day=212+day;break;
case 9:day=243+day;break;
case 10:day=273+day;break;
case 11:day=304+day;break;
case 12:day=334+day;break;
}
}
printf("2008年8月8日是该年的第%d天",day);
return 0;
}
这样也是对的
1回答
-
- qq_慕神1524904
- 2020-02-28 15:27:37
#include <stdio.h> int main() { int year = 2008; int month = 8; int day = 8; int sum; switch(month) { case 1:sum=0;break; case 2:sum=31;break; case 3:sum=59;break; case 4:sum=90;break; case 5:sum=120;break; case 6:sum=151;break; case 7:sum=181;break; case 8:sum=212;break; case 9:sum=243;break; case 10:sum=273;break; case 11:sum=304;break; case 12:sum=334;break; } sum+=day; if((year%4==0&&year%100!=0)||year%400==0) { sum++; break; } printf("%d年%d月%d日是该年的第%d天",year,month,day,sum); }
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