关于normalize函数record[i,:] != 0
来源：3-2 -电影推荐系统-构建模型
qq_三斤_0
2020-02-07 10:55
record[i,:] != 0这个能获取!=0的列下标吗，大家也偶人试了没，我这不行的
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- qq_三斤_0
- 2020-02-07 11:16:08
# 我改成了这样可以运行 for i in range(m): #获取一部电影评分用户的id ids = np.nonzero(record[i])[0] #ids = record[i,:] != 0 rating_mean[i] = np.mean(rating[i,ids]) #rating_norm[i,ids] -= rating_mean[i] rating_norm[i,ids] = rating[i,ids] - rating_mean[i] print("The row is {},mean rating is {},rating user size is {}" .format(i,rating_mean[i],ids.shape))
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