是不是我把switch理解错了
qq_慕仙6406143
2019-10-27 15:22
#include <stdio.h>
int main()
{
/* 定义需要计算的日期 */
int year = 2008;
int month = 8;
int day = 8;
switch(month)
case 1:
sum = day;
printf("%d",sum);
break;
case 2:
sum = 30 + day;
printf("%d",sum);
break;
case 3:
if(year % 4 == 0 && year % 100 != 0)
{
sum = 30 + 29 + day
}
else
{
sum = 30 + 28 + day
}
break;
case 4:
if(year % 4 == 0 && year % 100 != 0)
{
sum = 30 + 29 + 31 + day
}
else
{
sum = 30 + 28 + 31 + day
}
break;
case 5:
if(year % 4 == 0 && year % 100 != 0)
{
sum = 30 + 29 + 31 + 30 + day
}
else
{
sum = 30 + 28 + 31 + 30 + day
}
break;
case 6:
if(year % 4 == 0 && year % 100 != 0)
{
sum = 30 + 29 + 31 + 30 + 31 + day
}
else
{
sum = 30 + 29 + 31 + 30 + 31 + day
}
printf("%d",sum);
break;
case 7:
if(year % 4 == 0 && year % 100 != 0)
{
sum = 30 + 29 + 31 + 30 + 31 + 30 + day
}
else
{
sum = 30 + 29 + 31 + 30 + 31 + 30 + day
}
printf("%d",sum);
break;
case 8:
if(year % 4 == 0 && year % 100 != 0)
{
sum = 30 + 29 + 31 + 30 + 31 + 30 + 31 + day
}
else
{
sum = 30 + 29 + 31 + 30 + 31 + 30 + 31 + day
}
printf("%d",sum);
break;
case 9:
if(year % 4 == 0 && year % 100 != 0)
{
sum = 30 + 29 + 31 + 30 + 31 + 30 + 31 + 31 + day
}
else
{
sum = 30 + 29 + 31 + 30 + 31 + 30 + 31 + 31 + day
}
printf("%d",sum);
break;
case 10:
if(year % 4 == 0 && year % 100 != 0)
{
sum = 30 + 29 + 31 + 30 + 31 + 30 + 31 + 31 + 30 + day
}
else
{
sum = 30 + 29 + 31 + 30 + 31 + 30 + 31 + 31 + 30 + day
}
printf("%d",sum);
break;
case 11:
if(year % 4 == 0 && year % 100 != 0)
{
sum = 30 + 29 + 31 + 30 + 31 + 30 + 31 + 31 + 30 + 31 + day
}
else
{
sum = 30 + 29 + 31 + 30 + 31 + 30 + 31 + 31 + 30 + 31 + day
}
printf("%d",sum);
break;
default :
if(year % 4 == 0 && year % 100 != 0)
{
sum = 30 + 29 + 31 + 30 + 31 + 30 + 31 + 31 + 30 + 31 + 30 +
day
}
else
{
sum = 30 + 29 + 31 + 30 + 31 + 30 + 31 + 31 + 30 + 31 + 30 +
day
}
printf("%d",sum);
break;
/*
* 请使用switch语句，if...else语句完成本题
* 如有想看小编思路的，可以点击左侧任务中的“不会了怎么办”
* 小编还是希望大家独立完成哦~
*/
return 0;
}
1回答
-
- 白嫖小王子
- 2019-10-27 16:28:16
哪里不会？
C语言入门
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