2回答

• 

  老猿

  2019-07-18 13:25:08

  可以的呀，同学。可以这样写，例如：query.select(User.class, info->info.getColumn().equals("id"));

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  慕丝1577...

  了解..

  2019-07-20 19:04:37

  共 1 条回复 >

• 

  忙碌的程序猿

  2020-10-01 14:36:36

  query.select(User.class, !info->info.getColumn().equals("id"));

  这样写排除不了id，结果集id还是会显示出来。

  @Test
  public void selectPartOfColumns(){
      QueryWrapper<User> qw = new QueryWrapper<>();
      qw.like("name","雨").gt("age",20)
              .select(User.class,c -> !c.getColumn().equals("id")
              );
      List<User> list = userMapper.selectList(qw);
      list.forEach(System.out::println);
  }

  
  

  DEBUG==>  Preparing: SELECT id,create_time,name,manager_id,email,age FROM user WHERE (name LIKE ? AND age > ?) 

  DEBUG==> Parameters: %雨%(String), 20(Integer)

  TRACE<==    Columns: id, create_time, name, manager_id, email, age

  TRACE<==        Row: 1094590409767661570, 2019-01-14 09:15:15, 张雨琪, 1088248166370832385, zjq@baomidou.com, 31

  TRACE<==        Row: 1094592041087729666, 2019-01-14 09:48:16, 刘红雨, 1088248166370832385, lhm@baomidou.com, 32

  DEBUG<==      Total: 2

  User(id=1094590409767661570, name=张雨琪, age=31, email=zjq@baomidou.com, managerId=1088248166370832385, createTime=2019-01-14T09:15:15)

  User(id=1094592041087729666, name=刘红雨, age=32, email=lhm@baomidou.com, managerId=1088248166370832385, createTime=2019-01-14T09:48:16)

  
  

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