想不明白，代码应该没错吧，为什么输不出x%y
慕九州6316809
2019-02-03 18:19
#include <stdio.h>
int main()
{
int x,y;
x = 10;
y = -3;
printf("x+y=%d\n",x+y);
printf("x-y=%d\n",x-y);
printf("x*y=%d\n",x*y);
printf("x/y=%d\n",x/y);
printf("x%y=%d\n",x%y);
return 0;
}
3回答
-
- _啦_啦_啦_
- 2019-02-22 16:26:24
#include <stdio.h>
int main()
{
int x,y;
x = 10;
y = -3;
printf("x+y=%d\n",x+y );
printf("x-y=%d\n", x-y );
printf("x*y=%d\n",x*y );
printf("x/y=%d\n", x/y );
printf("x%%y=%d\n",x%y );
return 0;
}
-
- 慕九州6316809
- 2019-02-05 16:36:26
好的谢谢你
-
- 慕码人8457269
- 2019-02-03 21:24:09
#include <stdio.h>
int main()
{
int x,y;
x = 10;
y = -3;
printf("x+y=%d\n", x+y );
printf("x-y=%d\n", x-y );
printf("x*y=%d\n", x*y );
printf("x/y=%d\n", x/y );
printf("x%%y=%d\n", x%y );
return 0;
}
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