1回答

• 

  逐光阴影

  2018-11-04 20:17:54

  #include <stdio.h>

  int main() 

  { 

      /* 定义需要计算的日期 */

      int year = 2008;

      int month = 8;

      int day = 8;

      int m;

      int sum=0;

      if(year%4==0&&year%100!=0||year%400==0)   //这行的两个符号你的程序里是错的
  

          m=29;

          else

          m=28;

          switch(month)

      {

          case 1: sum=0;break;

          case 2: sum=31;break;

          case 3: sum=m+31;break;

          case 4: sum=m+31+31;break;

          case 5: sum=m+31+31+30;break;

          case 6: sum=m+31+31+30+31;break;

          case 7: sum=m+31+31+30+31+30;break;

          case 8: sum=m+31+31+30+31+30+31;break;

          case 9: sum=m+31+31+30+31+30+31+31;break;

          case 10: sum=m+31+31+30+31+30+31+31+30;break;

          case 11: sum=m+31+31+30+31+30+31+31+30+31;break;

          case 12: sum=m+31+31+30+31+30+31+31+30+31+30;break; 

          default:printf("您输入的月份有误！\n");break;

      }

      printf("2008年8月8日是该年的第%d天",sum+8);

      return 0;

  }

  
  

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