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怎么实现不了？

来源：4-15 编程练习

慕哥5975565

2018-05-11 22:51

* 判断一个数（小于10位）的位数。输入999，则输出 “它是个3位的数！”

int num = 999;

int count = 0;

if (num != 0 && num <= 999999999) {

do {

count++;

num = num / 10;

}

while{

(num<10);

}

System.out.println("它是个" + count + "位的数！");

} else{

System.out.println("输入有误");

}

写回答关注

5回答

慕沐9437088

2018-05-11 23:40:41

已采纳

public class HelloWorld{
public static void main(String[] args){
int num = 999;
int count = 0;

if (num >= 0 && num <= 999999999) {
do {
count++;
num /= 10;
}while(num>=1);

System.out.println("它是个" + count + "位的数！");
} else{
System.out.println("输入有误");
}
}
}

4 0

慕无忌592...

你换个数字输出一下就会有问题，不要999，你换100数出的值是2位数，求解决？

2018-05-25 15:06:09

共 4 条回复 >
合山川

2018-05-28 10:27:22

do while有bug吧

0 0
慕无忌5921142

2018-05-25 15:08:56

public static void main(String[] args){
Scanner sr=new Scanner(System.in);
int num =sr.nextInt();
int count = 0;
if (num > 0 && num <= 1000000) {
while(num!=0) {
count++;
num/=10;
}
System.out.println("它是"+count+"位数");
}else {
System.out.println("输出错误！");
}

}
}

0 0
慕无忌5921142

2018-05-25 14:58:57

Scanner sr=new Scanner(System.in);
int num =sr.nextInt();
int count = 0;
if (num != 0 && num <= 999999999) {
do {
count++;
num/=10;
}while(num>1);
System.out.println("它是"+count+"位数");
}else {
System.out.println("输出错误！");
}

}
为啥输入数字会减少一位数

3 0

慕粉1706...

while(num>0);

2018-06-27 00:10:04

共 3 条回复 >
qq_雨落_7

2018-05-11 23:13:48

public class HelloWorld{
public static void main(String[] args){
int num = 999;
int count = 0;
do
{
count++;
num=num/10;
}
while(num >0&&num<=999999999);

System.out.println("它是个" + count + "位的数！");
}
}

0 0