1回答

• 

  Akane_miku

  2018-03-22 12:51:57

  switch-case的简单计算器

  #include <stdio.h>

  int main( )

  {

  double a, b;

    char op;

    scanf("%lf%c%lf", &a, &op, &b);

    switch (op)

    {

        case  '+':

      printf("%lf + %lf = %lf\n", a, b, a + b);

    break;

    case  '-':

      printf("%lf - %lf = %lf\n", a, b, a - b);

    break; 

    case  '*':

  printf("%lf * %lf = %lf\n", a, b, a * b);

    break;

    case  '/':

    if (b != 0)

    printf("%lf / %lf = %lf\n", a, b, a / b);

    else

      printf("除数不能是0! \n");

    break;

    }

  }

  
  

  0 0