谁能帮我看一下,怎么解决,怎么实现分页效果呢?现在做了一半,

来源:3-6 控制类名(className 属性)

懒姑娘要学习了

2017-12-08 15:57

<!DOCTYPE html>

<html>

<head>

<meta charset="UTF-8">

<title></title>

<style type="text/css">

*{padding: 0;margin: 0;}

ul li{width: 30px;height: 30px;line-height: 30px;text-align: center;border: 1px solid #ccc;float: left;

margin-right: 0.5em;list-style: none;cursor: pointer;}

ul li:first-child,li:last-child{border: none;padding-right: .5em;}

.active{background: #555;color: #fff;}

li:first-child::before{content: "\00AB";margin-right: .3em;}

li:last-child::after{content: "\00BB";margin-left: .3em;}

</style>

</head>

<body>

<ul>

<li>pre</li>

<li class="active">1</li>

<li>2</li>

<li>3</li>

<li>4</li>

<li>5</li>

<li>next</li>

</ul>

<script type="text/javascript">

window.onload=function(){

var li=document.getElementsByTagName('li');

var before=document.getElementsByClassName('active');

for(var i=1;i<li.length-1;i++){

li[i].onclick=function(){

this.className='active';

// before.className='';

}

}

}

</script>

</body>

</html>


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3回答

  • lglong519
    2017-12-10 17:48:50
    已采纳
    <script type="text/javascript">
                window.onload=function(){
                    var li=document.getElementsByTagName('li');
                    var before=document.getElementsByClassName('active');
                    for(var i=0;i<li.length;i++){
                        //闭包获取当前i
                       (function(i) {
                           li[i].onclick=function(){
                            //如果是数字按钮则切换,将当前按钮class设置为active
                            if(i>0&&i<li.length-1){
                                if(this.className.indexOf('active')==-1){
                                    before[0].className='';
                                    this.className='active';
                                }
                                //如果不是数字按钮,先获得active标签的下标,然后根据左右按钮的点击设置对应位置的按钮为active
                            }else{
                                for(var n=1;n<li.length-1;n++){
                                    if(li[n].className.indexOf('active')>-1){
                                        break;
                                    }
                                }
                                //如果是左按钮
                                if(i==0&&n!=1){
                                    before[0].className='';
                                    li[--n].className='active';
                                //如果是右按钮
                                }else if(i==li.length-1&&n!=li.length-2){
                                    before[0].className='';
                                    li[++n].className='active';
                                }
                            }
                        }
                       })(i);
                        
                    }
                }
            </script>

    按钮的切换可以,具体内容也可以根据i或n切换一

    懒姑娘要学习...

    非常感谢!

    2017-12-11 10:51:05

    共 1 条回复 >

  • 懒姑娘要学习了
    2017-12-08 16:59:30
    <!DOCTYPE html>
    <html>
    	<head>
    		<meta charset="UTF-8">
    		<title></title>
    		<style type="text/css">
    			*{padding: 0;margin: 0;}
    			ul li{width: 30px;height: 30px;line-height: 30px;text-align: center;border: 1px solid #ccc;float: left;
    				margin-right: 0.5em;list-style: none;cursor: pointer;}
    			ul li:first-child,li:last-child{border: none;padding-right: .5em;}
    			.active{background: #555;color: #fff;}
    			li:first-child::before{content: "\00AB";margin-right: .3em;}
    			li:last-child::after{content: "\00BB";margin-left: .3em;}
    			
    		</style>
    	</head>
    	<body>
    		<ul>
    			<li>pre</li>
    			<li class="active">1</li>
    			<li>2</li>
    			<li>3</li>
    			<li>4</li>
    			<li>5</li>
    			<li>next</li>	
    		</ul>
    		<script type="text/javascript">
    			window.onload=function(){
    				var li=document.getElementsByTagName('li');
    				var before=document.getElementsByClassName('active');
    				for(var i=1;i<li.length-1;i++){
    					li[i].onclick=function(){
    						this.className='active';
    //						before.className='';
    					}
    				}
    			}
    		</script>
    	</body>
    </html>


  • 半分笑似假
    2017-12-08 16:51:11

    代码一排,太不规范了

    懒姑娘要学习...

    请你再看一眼

    2017-12-08 17:00:35

    共 1 条回复 >

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