get方法可以。post方法不可以
干巴爹forever
2017-10-31 20:34
index。jsp代码如下：
<%@ page language="java" import="java.util.*" contentType="text/html; charset=utf-8"%>
<%
String path = request.getContextPath();
String basePath = request.getScheme()+"://"+request.getServerName()+":"+request.getServerPort()+path+"/";
%>
<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN">
<html>
<head>
<base href="<%=basePath%>">
<title>My JSP 'index.jsp' starting page</title>
<meta http-equiv="pragma" content="no-cache">
<meta http-equiv="cache-control" content="no-cache">
<meta http-equiv="expires" content="0">
<meta http-equiv="keywords" content="keyword1,keyword2,keyword3">
<meta http-equiv="description" content="This is my page">
<!--
<link rel="stylesheet" type="text/css" href="styles.css">
-->
</head>
<body>
<h1>第一个servlet小例子</h1>
<a href="servlet/HelloServlet">get请求servlet</a><br>
<form action="servlet/HelloServlet" method="post">
<input type="submit" value="post请求servlet"/>
</body>
</html>
HelloServlet.java代码如下：
package servlet;
import java.io.IOException;
import java.io.PrintWriter;
import javax.servlet.ServletException;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
public class HelloServlet extends HttpServlet {
@Override
protected void doGet(HttpServletRequest request, HttpServletResponse response)
throws ServletException, IOException {
// TODO Auto-generated method stub
System.out.println("处理get()请求。。。。");
PrintWriter out=response.getWriter();
response.setContentType("text/html;charset=utf-8");
out.println("hello servlet!");
}
@Override
protected void doPost(HttpServletRequest request, HttpServletResponse response)
throws ServletException, IOException {
// TODO Auto-generated method stub
System.out.println("处理post()请求。。。。");
PrintWriter out=response.getWriter();
response.setContentType("text/html;charset=utf-8");
out.println("Hello servlet!");
}
}
2回答
-
- 慕妹7264492
- 2017-10-31 23:22:39
你的form结束标签呢？ </form>
<form action="servlet/HelloServlet" method="post">
<input type="submit" value="post请求servlet"/>
</form>
-
- 干巴爹forever
- 2017-11-01 19:54:02
加了</form>以后post确实可以用了，但是console面和老师的还是不一样，我的还是红红的一片。。
JAVA遇见HTML——Servlet篇
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