慕用4063026
2017-10-09 22:55
#include <stdio.h>
int main()
{
/* 定义需要计算的日期 */
int year = 2008;
int month = 8;
int day = 8;
switch(month)
{
case 12:day+=30;
case 11:day+=31;
case 10:day+=31;
case 9:day+=30;
case 8:day+=31;
case 7:day+=31;
case 6:day+=30;
case 5:day+=31;
case 4:day+=30;
case 3:day+=31;
case 2:if(year%4==0&&year%400!=0)
{day+=29;}else{day+=28;}
case 1:day;
printf("%d",day);
break;
}
return 0;
}
printf("%d年%d月%d日是该年的第%d天",year, month, day, sum);你可以试试改成这样
C语言入门
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