用按钮实现访问兄弟节点？怎样点了按钮不消失？
文刀笑
2017-08-01 12:07
function next(){
y=get_nextSibling(y);
if(y!=null){
document.write("<br />nextsibling: ");
document.write(y.nodeName);
document.write(" = ");
document.write(y.innerHTML);
}else{
document.write("<br>已经是最后一个节点");
}
<input type="button" value="next" onclick="next()"/>
2回答
-
- 学习js
- 2017-08-03 10:28:34
<!DOCTYPE HTML>
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8">
<title>nextSibling</title>
</head>
<body>
<ul id="u1">
<li id="a">javascript</li>
<li id="b">jquery</li>
<li id="c">html</li>
</ul>
<ul id="u2">
<li id="d">css3</li>
<li id="e">php</li>
<li id="f">java</li>
</ul>
<div id="u3"></div>
<input type="button" value="next" onclick="next()" />
<script type="text/javascript">
function get_nextSibling(n) {
var x = n.nextSibling;
while(x && x.nodeType != 1) {
x = x.nextSibling;
}
return x;
}
function get_previousSibling(n) {
var x = n.previousSibling;
while(x && x.nodeType != 1) {
x = x.previousSibling;
}
return x;
}
var x = document.getElementsByTagName("li")[0];
document.write(x.nodeName);
document.write(" = ");
document.write(x.innerHTML);
var y = get_nextSibling(x);
function next() {
y = get_nextSibling(y);
if(y != null) {
document.getElementById("u3").innerHTML="<br />next sibling: "+y.nodeName+"="+y.innerHTML
} else {
document.getElementById("u3").innerHTML="<br>已经是最后一个节点"
}
}
</script>
</body>
</html>
-
- 学习js
- 2017-08-01 16:43:17
写个div,把你要输出的内容放到新的div里面
JavaScript进阶篇
468059 学习 · 21891 问题
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