1回答

• 

  qq_番茄蛋花汤_0

  2017-03-19 19:34:02

  已采纳

  #include <stdio.h>

  int my_charge(float time,double km);

  
  

  int main()

  {

      double cost=0;

      cost=cost+my_charge(9,12);

      cost=cost+my_charge(18,12);

      printf("总费用是：%f",cost); 

      return 0;

      

  }

  int my_charge(float time,double km)

  {

      double danjia=2.3,qibu=13,cost=0;

      if(km<=3)

      {

          cost=14;

      }

      else

      {

          cost=13+(km-3)*2.3+1;

      }

      if ((time>=23&&time<=24)||(time>=0&&time<=6))

      {

          cost=cost*1.2;

      }

      return cost;

  }

  
  

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