5回答

• 

  通信IT狗

  2016-10-25 14:29:00

  已采纳

  • 代码第4行有问题，你将变量mydate进行了重新的赋值，返回类型变成了数字，所以下面的mydate.getDay()无法正常运行

  • 其实将第四行的变量名字改变一下，不与日期变量mydate重复就行
    

  1 1

  孤独的小猪

  非常感谢！

  2016-10-25 14:44:43

  共 1 条回复 >

• 

  慕哥7653536

  2016-10-25 16:44:35

  <script type="text/javascript">

    var mydate = new Date();

    var day=mydate.getDay();

    var myyear=mydate.getFullYear();

    var mymonth=mydate.getMonth()+1;

    var mydate=mydate.getDate();

    var weekday=["星期日","星期一","星期二","星期三","星期四","星期五","星期六"];

     var myweek=weekday[day];

    document.write(myyear+"年"+mymonth+"月"+mydate+"日"+myweek);

  </script>

  
  

  当把var day=mydate.getDay();这行代码提到var mydate = new Date();下面一行的时候，就能正常运行了。

  至今不知道什么原因，应该是代码验证系统的bug吧。

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• 

  慕哥7653536

  2016-10-25 16:42:38

  <script type="text/javascript">

    var mydate = new Date();

    var day=mydate.getDay();

    var myyear=mydate.getFullYear();

    var mymonth=mydate.getMonth()+1;

    var mydate=mydate.getDate();

    var weekday=["星期日","星期一","星期二","星期三","星期四","星期五","星期六"];

    

    var myweek=weekday[day];

    document.write(myyear+"年"+mymonth+"月"+mydate+"日"+myweek);

  </script>

  
  

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• 

  年轻的心大胆做

  2016-10-25 14:20:41

  ['星期日','星期一','星期二','星期三','星期四','星期五','星期六'];    应该是双引号把

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• 

  语兮

  2016-10-25 14:16:40

  var mydate = new Date();
  var myyear = mydate.getFullYear();
  var mymonth = mydate.getMonth()+1;
  var myday = mydate.getDate();
  var weekday = ['星期日','星期一','星期二','星期三','星期四','星期五','星期六'];
  var week = weekday[mydate.getDay()];
  document.write(myyear+'年'+mymonth+'月'+myday+'日'+week);

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