提示不能为空的功能实现不了？
LebronJames_
2016-07-20 22:35
不填写内容，直接提交，出现下面的错误提示：
警告: Could not find action or result
No result defined for action loginDemo.loginAction and result input
at com.opensymphony.xwork2.DefaultActionInvocation.executeResult(DefaultActionInvocation.java:375)
at com.opensymphony.xwork2.DefaultActionInvocation.invoke(DefaultActionInvocation.java:277)
at com.opensymphony.xwork2.validator.ValidationInterceptor.doIntercept(ValidationInterceptor.java:263)
at org.apache.struts2.interceptor.validation.AnnotationValidationInterceptor.doIntercept(AnnotationValidationInterceptor.java:68)
at com.opensymphony.xwork2.interceptor.MethodFilterInterceptor.intercept(MethodFilterInterceptor.java:98)
.....
login.jsp部分代码
%@ page language="java" import="java.util.*" contentType="text/html; charset=utf-8"%> <%@ taglib prefix="s" uri="/struts-tags"%> ...... <body> <form action="loginAction.action" method="post"> 用户名： <input type="text" name="username"><s:fielderror name="username"></s:fielderror> 密码： <input type="password" name="password"> 书籍1： <input type="text" name="bookList[0].username"> 书籍2： <input type="text" name="bookList[1].username"> <input type="submit" value="提交"/> </form> </body>
web.xml部分代码
<filter> <filter-name>struts2</filter-name> <filter-class>org.apache.struts2.dispatcher.ng.filter.StrutsPrepareAndExecuteFilter</filter-class> </filter> <filter-mapping> <filter-name>struts2</filter-name> <url-pattern>/*</url-pattern> </filter-mapping>
loginAction 部分代码
public void validate() {
if(user.getUsername() == null
||"".equals(user.getUsername())){
this.addFieldError("username","用户名不能为空");
}
}4回答
-
- 二度
- 2016-07-28 11:03:20
<action name="loginAction" method="login" class="loginDemo.loginAction">
<result name="input">/success.jsp </result>
</action>
-
- 柚子KiYou丶
- 2016-07-31 20:52:29
楼上正解，result的name默认类型是success。
-
- LebronJames_
- 2016-07-20 23:43:24
struts.xml
<?xml version="1.0" encoding="UTF-8"?> <!DOCTYPE struts PUBLIC "-//Apache Software Foundation//DTD Struts Configuration 2.1//EN" "http://struts.apache.org/dtds/struts-2.1.dtd"> <struts> <package name="default" namespace="/" extends="struts-default"> <action name="loginAction" method="login" class="loginDemo.loginAction"> <result >/success.jsp </result> </action> </package> </struts>
-
- 柚子KiYou丶
- 2016-07-20 23:13:51
action和result的xml贴出来看看
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