6回答

• 

  保龙

  2016-05-18 12:56:47

  已采纳

  你new错了，要new Player类

  <?php

  class Human{

  public $name;

  public $height;

  public $weight;

  
  

  public function eat($food){

  echo $this->name."'s eating ".$food."\n";

  }

  }

  
  

  class Player extends Human{

  function __construct($name,$height,$weight){

  $this->name=$name;

  $this->height=$height;

  $this->weight=$weight;

  }

  }

  
  

  $jor = new Player("jor","198cm","75kg");

  echo $jor->name."\n";

  $jor->eat("orange");

  ?>

  
  

  1 0

  祁望

  可以了，非常感谢！

  2016-05-18 13:39:03

  共 1 条回复 >

• 

  qq_一場煙火半世迷離_0

  2016-07-14 11:42:37

  new  子类不是父类

  0 0
• 

  祁望

  2016-05-16 10:44:53

  可不可以帮我把代码直接改好啊？我把构造函数加入Human类里，name也没出来

  0 0
• 

  ewang1986

  2016-05-14 14:15:34

  构造函数加到Human类里面

  0 0
• 

  祁望

  2016-05-12 11:50:50

    <p><?php

  class Human

  {

  public $name;

  public $height;

  public $weight;

  public function eat($food){

  echo $this ->name."'s eating ".$food."\n";

  }

  }

  class Player extends Human 

  {

  function __construct($name,$height,$weight)

  $this->name=$name;

  $this->height=$height;

  $this->weight=$weight;

  }

  
  

  $jor=new Human("jor","198cm","75kg");

  echo $jor ->name."\n";

  $jor ->eat("orange");

  ?>

  加了构造函数还是没显示

  0 0
• 

  Nick_Li551

  2016-05-12 10:46:53

  你没写构造函数，你的数据没有录进去$jor里面，$jor用的是你定义的类里面的原来的name height weight 就是空的
  

  0 0