$*不用双引号的话循环输出多个
苏小闲
2016-01-06 22:27
老师好哈，我写的for区分$*下面这样也循环多次输出呢，为啥啊
#!/bin/bash
#for区分$*和$@
for i in $* #区别在这里,&*没有双引号，有了双引号就循环一次，没有则会多次
do
echo "\$*:$i"
done
for j in $@
do
echo "\$@:$j"
done
//运行结果如下
$*:11
$*:22
$*:33
$*:44
$@:11
$@:22
$@:33
$@:44
1回答
-
- jxm080511321
- 2016-01-07 02:04:19
#!/bin/bash
set 'apple pie' pears peaches
for i in $* /*单引号被去掉，循环单个字符输出*/
do echo $idone
[root@luozhonghua Ex_14.02-14.31]# sh 14-14-1
apple
pie
pears
peaches--------------------------------------------------------------
#!/bin/bash
set 'apple pie' pears peaches
for i in "$*" /*单引号被去掉，但当作字符串一次输出*/
do echo $i
done[root@luozhonghua Ex_14.02-14.31]# sh 14-14-2
apple pie pears peaches
[root@luozhonghua Ex_14.02-14.31]#-----------------------------------------------------------------
#!/bin/bash
set 'apple pie' pears peaches
for i in $@ /*单引号被去掉，循环单个字符输出*/
do echo $i
done
[root@luozhonghua Ex_14.02-14.31]# sh 14-14-3
apple
pie
pears
peaches-----------------------------------------------------------------
#!/bin/bash
set 'apple pie' pears peaches
for i in "$@" /*每个位置参数都将当成一个加引号的字符串:"apple pie","pears ","peaches"*/
do echo $i
done
[root@luozhonghua Ex_14.02-14.31]# sh 14-14-4
apple pie
pears
peaches
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