请问为什么得出的结果全都是30 ？啥意思啊
hurry_君君
2016-01-01 11:44
package com.waiting;
public class Test {
public static void main(String[] args) {
int one = 10 ;
int two = 20 ;
int three = 0 ;
three=one+two;
three+=one;
three-=one;
three*=one;
three/=one;
System.out.println("three=one+two==>"+three);
System.out.println("three+=one==>"+three);
System.out.println("three-=one==>"+three);
System.out.println("three*=one==>"+three);
System.out.println("three/=one==>"+three);
System.out.println("three%=one==>"+three);
请问 有人帮我解答下吗？这个代码是不是应该这样写？结果怎么全都是最后一个数 30 30 30 3 0.。。。。啥意思啊
3回答
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- 慕莱坞9220042
- 2016-01-01 12:06:11
你好，这么写：
public class HelloWorld{ public static void main(String[] args) { int one = 10 ; int two = 20 ; int three = 0 ; three = one +two; System.out.println("three = one + two ==>" + three); three += one; System.out.println("three += one ==>" + three); three -= one; System.out.println("three -= one ==>" + three); three *=one; System.out.println("three *= one ==>" + three); three /=one; System.out.println("three /= one ==>" + three); three %=one; System.out.println("three %= one ==>" + three); } }你的问题是把所有的运行语句执行后，最后输出的，肯定结果都一样，应该执行一条输出一条，不然后会覆盖，
望楼主采纳！
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- 我爱吃青椒
- 2016-01-02 14:44:45
只输出最后的结果，如果想把每一步的结果都输出，那么要在每一步后面都有个sysout
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- 萝卜特Scream
- 2016-01-01 12:11:12
肯定是30，只输出最后一个计算结果
int one = 10 ; int two = 20 ; int three = 0 ; three=one+two;System.out.println("three=one+two==>"+three); three+=one;System.out.println("three+=one==>"+three); three-=one;System.out.println("three-=one==>"+three); three*=one;System.out.println("three*=one==>"+three); three/=one;System.out.println("three/=one==>"+three);
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