为什么我只得到“0”输出？

Question

我试图搜索文本文件并确定文本文件中有多少行、元音、辅音和数值/字符。我的元音、辅音和数字输出值似乎没有正确计算。线路输出总计已正确计算。

ein = input("Please enter file name: ")

vowels = set("AEIOUaeoiu")

cons = set("BCDFGHJKLMNPQRSTVWXYZbcdfghjklmnpqrstvwvyz")

num = set("1234567890")

count = 0

Vcount = 0

Ccount = 0

Ncount = 0

with open(ein) as ein_handle:

    for line in ein_handle:

        count += 1

    for line in ein_handle:

        if line in vowels:

            Vcount += 1

        elif line in cons:

            Ccount += 1

        elif line in num:

            Ncount += 1

print("the file has",count,"lines.")

print("the file has",Vcount,"vowels.")

print("the file has",Ccount,"consonants.")

print("the file has",Ncount,"numerical characters.")

Answer 1

第二个循环应该针对给定行中的每个字符。试试这个：ein = input("Please enter file name: ")vowels = set("AEIOUaeoiu")cons = set("BCDFGHJKLMNPQRSTVWXYZbcdfghjklmnpqrstvwvyz")num = set("1234567890")count = 0Vcount = 0Ccount = 0Ncount = 0with open(ein) as ein_handle:    for line in ein_handle:        count += 1        for letter in line:            if letter in vowels:                Vcount += 1            elif letter in cons:                Ccount += 1            elif letter in num:                Ncount += 1print("the file has", count, "lines.")print("the file has", Vcount, "vowels.")print("the file has", Ccount, "consonants.")print("the file has", Ncount, "numerical characters.")另外，在第二个循环内得到 0 （而不是行数）的主要原因是因为当第一个循环执行时，它会在每次迭代时更新读取偏移位置，直到它结束。因此，当第二个循环开始时，它从文件末尾开始，无法读取任何内容。

Answer 2

这是另一种方法：import osd,_ = os.path.split(__file__)ein = input("Please enter file name: ")vowels = "aeoiu"cons = "bcdfghjklmnpqrstvwvyz"num = "1234567890"Vcount = 0Ccount = 0Ncount = 0with open(d+"\\" + ein) as ein_handle:    lines = ein_handle.readlines()    for line in lines:        line = line.lower()        for v in vowels:            tmp = line            while v in tmp:                Vcount += 1                tmp = tmp[tmp.find(v)+1:]        for c in cons:            tmp = line            while c in tmp:                Ccount += 1                tmp = tmp[tmp.find(c)+1:]        for n in num:            tmp = line            while n in tmp:                Ncount += 1                tmp = tmp[tmp.find(n)+1:]print("the file has",len(lines),"lines.")print("the file has",Vcount,"vowels.")print("the file has",Ccount,"consonants.")print("the file has",Ncount,"numerical characters.")