我有以下代码从 mysql 数据库读取数据。不幸的是我似乎找不到删除这个的方法"status": {
这是代码片段
// required headers
header("Access-Control-Allow-Origin: *");
header("Content-Type: application/json; charset=UTF-8");
// database connection will be here
// include database and object files
include_once '../config/database.php';
include_once '../objects/status.php';
// instantiate database and status object
$database = new Database();
$db = $database->getConnection();
// initialize object
$status = new Status($db);
// query status
$stmt = $status->read();
$num = $stmt->rowCount();
// check if more than 0 record found
if($num>0){
// status array
$status_arr=array();
$status_arr["status"]=array();
// retrieve our table contents
// fetch() is faster than fetchAll()
// http://stackoverflow.com/questions/2770630/pdofetchall-vs-pdofetch-in-a-loop
while ($row = $stmt->fetch(PDO::FETCH_ASSOC)){
// extract row
// this will make $row['name'] to
// just $name only
extract($row);
$status_item = array(
"id" => $status_id,
"name" => html_entity_decode($status_name),
"created" => $status_created,
"modified" => $status_modified,
"state" => $status_state
);
array_push($status_arr["status"], $status_item);
}
// set response code - 200 OK
http_response_code(200);
// show status data in json format
echo json_encode(
array("response_code" => 0, "response_message" => "Request processed successfully", "status" => $status_arr)
);
}
else{
// set response code - 404 Not found
http_response_code(404);
// tell the user no status found
echo json_encode(
array("response_code" => 1, "response_message" => "No status found.")
);
请注意，在所需的输出中不应有 "status": {}，而应仅具有 "status": []。我应该对上面提供的代码进行哪些修改？
MMTTMM