如何获取两个月/年点之间的每个月数和年份

5回答

牛魔王的故事

您可以使用 PHP 的DateInterval类来实现这些目的。试试这个代码<?phpfunction getMonthsFromRange($start, $end, $format = 'M Y'){ $array = array(); // Since you wanted 1 month it is Period = 1 Month $interval = new DateInterval('P1M'); $realEnd = new DateTime($end); $realEnd->add($interval); $period = new DatePeriod(new DateTime($start), $interval, $realEnd); // Use loop to store date into array foreach ($period as $date) $array[] = $date->format($format); // Return the array elements return $array;}// Function call with passing the start date and end date $months = getMonthsFromRange('2010-10', '2011-11');print_r($months);它的输出是：Array ( [0] => Oct 2010 [1] => Nov 2010 [2] => Dec 2010 [3] => Jan 2011 [4] => Feb 2011 [5] => Mar 2011 [6] => Apr 2011 [7] => May 2011 [8] => Jun 2011 [9] => Jul 2011 [10] => Aug 2011 [11] => Sep 2011 [12] => Oct 2011 [13] => Nov 2011 )

胡说叔叔

只需在开始日期上添加 1 个月直到结束日期即可完成...function get_all_months($monthstart = null, $yearstart = null, $monthend = null, $yearend = null) { $output = []; $time = strtotime($yearstart."-".$monthstart); $last = date('m-Y', strtotime($yearend."-".$monthend)); do { $month = date('m-Y', $time); $output[] = $month; $time = strtotime('+1 month', $time); } while ($month != $last); return $output;}所以print_r(get_all_months(4,2008,2,2010));给...Array( [0] => 04-2008 [1] => 05-2008 [2] => 06-2008 [3] => 07-2008 [4] => 08-2008 [5] => 09-2008 [6] => 10-2008 [7] => 11-2008 [8] => 12-2008 [9] => 01-2009 [10] => 02-2009 [11] => 03-2009 [12] => 04-2009 [13] => 05-2009 [14] => 06-2009 [15] => 07-2009 [16] => 08-2009 [17] => 09-2009 [18] => 10-2009 [19] => 11-2009 [20] => 12-2009 [21] => 01-2010 [22] => 02-2010)

墨色风雨

也许你正在寻找这样的东西：function get_all_months($monthstart = null, $yearstart = null, $monthend = null, $yearend = null) {    $month_array = [];    if ($yearstart == $yearend)        for ($m=$monthstart; $m<=$monthend; $m++) $month_array[] = array('month' => $m, 'year' => $yearstart);    else {        for ($m=$monthstart; $m<=12; $m++) $month_array[] = array('month' => $m, 'year' => $yearstart);        for ($y=$yearstart+1; $y<$yearend; $y++) for ($m=1; $m<=12; $m++) $month_array[] = array('month' => $m, 'year' => $y);        for ($m=1; $m<=$monthend; $m++) $month_array[] = array('month' => $m, 'year' => $yearend);    }    return $month_array;}

HUWWW

使用DateTime类和DateInterval，您可以创建指定范围的 DateTime 对象的生成器：<?phpfunction get_all_months(int $monthstart, int $yearstart, int $monthend, int $yearend) { $onemonth = new DateInterval('P1M'); // one month interval $timeperiod = new DatePeriod( DateTime::createFromFormat('Y-m', "{$yearstart}-{$monthstart}"), $onemonth, DateTime::createFromFormat('Y-m', "{$yearend}-{$monthend}")->add($onemonth) ); foreach ($timeperiod as $pos) { yield clone $pos; }}foreach (get_all_months(12, 2009, 1, 2020) as $month) { echo "{$month->format('Y-m')}\n";}DateTime 应该比普通字符串或数字数组更灵活地使用

函数式编程

如果我理解正确的话 - 你会得到数字形式的月份和数字形式的年份，例如 6 和 1997。如果我们假设开始年份总是小于结束年份，我建议这样做。function distanceBetweenDates(int $sm, int $sy, int $em, int $ey) {    $monthsBetweenYears = ($ey - $sy + 1) * 12;    $distanceBetweenMonths = $monthsBetweenYears - $sm - (12 - $em);        $startMonth = $sm + 1;    $startYear = $sy;        while ($distanceBetweenMonths > 0) {        if ($startMonth <= 12) {            echo $startMonth . ' - ' . $startYear;        } else {            $startMonth = 1;            $startYear++;            echo $startMonth . ' - ' . $startYear;        }        echo "\n";        $startMonth++;        $distanceBetweenMonths--;    }}您可能需要查看的唯一事情是计算中是否包含或排除给定的月份。这里唯一缺少的是验证，因为如果您在方法内使用类型，则可以“跳过”某种验证。