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繁花不似锦
这只是将 json 字符串简单地复制/粘贴到 AndroidStudio 中，它会自动分割字符串并添加转义斜杠。它看起来很糟糕，但你编写的语法完全没问题。 String jsonString = " {\n" + " \"query\": {\n" + " \"bool\": {\n" + " \"must\": [\n" + " {\"match\": \n" + " { \"customer.partnerName\": \"Synapse\" }},\n" + "\n" + " {\n" + "\"range\" : \n" + "{\n" + " \"customer.billing.chargeAmount\" : {\n" + " \"gte\" : 1,\n" + " \"lte\" : 100\n" + " }\n" + " }}\n" + " ],\n" + " \"filter\": [\n" + " { \"match\": { \"customer.configId\": 15 }}\n" + " ]\n" + " }\n" + " }\n" + " }"; // HERE BEAUTIFIED /*jsonString = "{\"query\":{\"bool\":{\"must\":[{\"match\":{\"customer.partnerName\":\"Synapse\"}},{\"range\":{\"customer.billing.chargeAmount\":{\"gte\":1,\"lte\":100}}}],\"filter\":[{\"match\":{\"customer.configId\":15}}]}}}"; */ try { JSONObject object = new JSONObject(jsonString); // NO ERRORS, OBJECT CREATED IN MY CASE } catch (JSONException e) { e.printStackTrace(); }您拥有的第二个选项是以编程方式创建对象、内部对象和数组..就像这样.. try { JSONObject jsonObject = new JSONObject(); JSONObject query = new JSONObject(); jsonObject.put("query", query); JSONObject bool = new JSONObject(); query.put("bool", bool); JSONArray must = new JSONArray(); bool.put("must", must); JSONObject matchWrap = new JSONObject(); JSONObject match = new JSONObject(); match.put("customer.partnerName", "Synapse"); matchWrap.put("match", match); must.put(matchWrap); JSONObject rangeWrap = new JSONObject(); JSONObject range = new JSONObject(); JSONObject customerBillingChargeAmount = new JSONObject(); customerBillingChargeAmount.put("gte", 1); customerBillingChargeAmount.put("lte", 100); range.put("customer.billing.chargeAmount", customerBillingChargeAmount); rangeWrap.put("range", range); must.put(rangeWrap); JSONArray filter = new JSONArray(); bool.put("filter", filter); JSONObject match2Wrap = new JSONObject(); JSONObject match2 = new JSONObject(); match2.put("customer.configId", 15); match2Wrap.put("match", match2); filter.put(match2Wrap); String jsonString2 = jsonObject.toString(); // HERE THE SAME JSON STRING AS YOUR INPUT } catch (JSONException e) { e.printStackTrace(); }当删除空格、制表符、换行符等时，这会产生与输入字符串相同的结果。
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慕慕森
我认为你正在寻找的是 json 解析。这是通过以下方式完成的：JsonParser parser = new JsonParser();JsonObject object = (JsonObject) parser.parse(jsonData); //Insert json string data//Do other stuff
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万千封印
所以，我想说你应该使用 JsonPath lib 来做到这一点。 <dependency> <groupId>com.jayway.jsonpath</groupId> <artifactId>json-path</artifactId> <version>2.4.0</version> </dependency>使用示例import com.jayway.jsonpath.DocumentContext;import com.jayway.jsonpath.JsonPath;...public void handle(...) {... DocumentContext jsonContext = JsonPath.parse(responseBody); JSONArray jsonPathPreviousUrl = jsonContext.read("$..previous")...这将快速有效地解析您的 json。{ "feed": { "data": [ { "created_time": "2017-12-12T01:24:21+0000", "message": "This picture of my grandson with Santa", "id": "" }, { "created_time": "", "message": "", "id": "" }, { "created_time": "", "message": "", "id": "" } ], "paging": { "previous": "https://facebook/v3.2/{your-user-id}/feed?format=json&limit=3&since=1542820440", "next": "https://facebook/v3.2/{your-user-id}/feed?format=json&limit=3&until=1542583212&" } }, "id": "{your-user-id}"}}
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白猪掌柜的
<script>var txt = '{"query": {"bool": {"must": [{"match": { "customer.partnerName": "Synapse" }},{"range" : { "customer.billing.chargeAmount" : { "gte" : 1, "lte" : 100 } }}],"filter": [{ "match": { "customer.configId": 15 }}]}}}'var obj = JSON.parse(txt);debugger;document.getElementById("demo").innerHTML = obj.query;</script>
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互换的青春
您尝试过 Google gson 吗？这是 repo，你也可以在网上找到相关的实现。 https://github.com/google/gson