搜索文本以查看是否存在单词列表，如果存在，则返回该单词周围的文本？

Question

我有一个功能，当前可以搜索文本以查看其中是否提到了我的任何关键字。我想增强此功能以返回找到的关键字以及识别后的 25 个单词。我的代码如下，但由于“单词”未被识别而无法工作：

def searching(text):

    key_words = ["address","home", "location", "domicile"]

    if any(word in text for word in key_words):

        statement = text[text.find(word) + 1:].split()[0:20]

        my_return = " ".join(statement)

        return my_return 

    else:

        return "No result"

text = I have a pretty good living situation. I am very thankful for my home located in Massachusetts.

我希望我的函数返回“位于马萨诸塞州的家”，但我收到错误。

NameError: name 'word' is not defined

有任何想法吗？

Answer 1

您可以将字符串拆分为单词并检查结果列表。您正在函数中返回，因此它只是在第一次迭代后返回，您可以在参数中提供关键字。您期望的结果可以这样获得：def searching(text):    key_words = ["address","home", "location", "domicile"]    for word in key_words:        if word in text.split():            statement = text[text.find(word) + 0:].split()[0:20]            my_return = " ".join(statement)            print(my_return)        else:            print("No result")text = "I have a pretty good living situation. I am very thankful for my home located in Massachusetts."print(searching(text))输出No resulthome located in Massachusetts.No resultNo result要在第一次匹配时返回匹配项，您可以执行此操作并删除else.def searching(text):    key_words = ["address","home", "location", "domicile"]    for word in key_words:        if word in text.split():            statement = text[text.find(word) + 0:].split()[0:20]            my_return = " ".join(statement)            return my_returntext = "I have a pretty good living situation. I am very thankful for my home located in Massachusetts. You can find me at my address 123 Happy Lane."print(searching(text))输出address 123 Happy Lane.