删除包含相同字母超过3次的行

Question

我有这段代码，如果行 3 次包含相同的字母，则删除行。如果字母重复超过 3 次（分隔），我需要它来删除该行。

3次（分开）我的意思是例如这一行BAABAAG。请注意，这一行包含该字母A四次，但我的代码没有删除它，因为这四个字母A并不彼此相邻。

bad_words = ['AAA','BBB','CCC','DDD','EEE','FFF','GGG','HHH','III','JJJ','KKK','LLL','MMM','NNN','OOO','PPP','QQQ','RRR','SSS','TTT','UUU','VVV','WWW','XXX','YYY','ZZZ','111','222','333','444','555','666','777','888','999','000']

with open('7.csv') as oldfile, open('new7.csv', 'w') as newfile:

    for line in oldfile:

        if not any(bad_word in line for bad_word in bad_words):

            newfile.write(line)

文件样本：

BAABAAB

BAABAAC

BAABAAD

BAABAAE

BAABAAF

BAABAAG

BAABAAH

BAABAAI

BAABAAJ

BAABAAK

BAABAAL

BAABAAM

BAABAAN

BAABAAO

BAABAAP

BAABAAQ

Answer 1

无需显式创建bad_words列表，您repeater也可以将其设置为变量repeater = 3newlist = []with open('input.txt') as f:        x = f.readlines()    for val in x:        word = val.split('\n')[0]        flag = True        for letter in word:            if letter.upper() * repeater in word:                flag = False                break        if flag:            newlist.append(word)    newlist = list(set(newlist))with open('output.txt', mode='w', encoding='utf-8') as newfile:    for value in newlist:        newfile.writelines(value+"\n")

Answer 2

您可以创建一个函数来检查某个字符是否出现超过 3 次，然后在代码中调用它：def letter_count(str):    counts = dict()    for l in str:        if l in counts:            counts[l] += 1        else:            counts[l] = 1    counts[max(counts, key=lambda x : counts[x])]    return counts[max(counts, key=lambda x : counts[x])] > 3并在您的代码中这样调用它：with open('7.csv') as oldfile, open('new7.csv', 'w') as newfile:    for line in oldfile:        if if(letter_count(line)):            newfile.write(line)

Answer 3

您可以使用 aCounter检查每行中不同字母的频率，然后仅在它们未通过阈值时才写入此行：from collections import Counterthreshold = 3with open('7.csv') as oldfile, open('new7.csv', 'w') as newfile:    for line in oldfile:        counts = Counter(line)        if all(count < threshold for count in counts.values()):            newfile.write(line)这使用该all()函数来确保没有字母超过阈值。

Answer 4

使用单个字符而不是三元组和 的列表string.count()。制作一个小函数来封装过滤逻辑可能也是一个不错的选择。def f(line, chars, limit):&nbsp; &nbsp; for char in chars:&nbsp; &nbsp; &nbsp; &nbsp; if line.count(char) > limit:&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; return False&nbsp; &nbsp; return Truebad_chars = ['A','B', ...]with open('7.csv', 'r') as oldfile, open('new7.csv', 'w') as newfile:&nbsp; &nbsp; for line in oldfile:&nbsp; &nbsp; &nbsp; &nbsp; if f(line, bad_chars, 3):&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; newfile.write(line)