如何在颜色条上均匀分布刻度？

Question

我一直在尝试在颜色栏中绘制一些均匀间隔的刻度线，但到目前为止，我的结果总是给我一个颜色条，刻度线之间的距离与其值成正比，如下图所示：

import numpy as np

import matplotlib

import matplotlib as plt

T= [0.01, 0.02, 0.03, 0.04] #values for the colourbar to use in equation in for loop

x=np.linspace[0, 8, 100]

e=1/(np.exp(x)+1)       #factor used in equation dependent on the x-axis values

a=6.4*10**(-9)         

b= 1.51                  # constants for the equation

pof6= [number **6 for number in T]

norm = matplotlib.colors.Normalize(vmin=np.min(pof6), vmax=np.max(pof6))  #colourbar max and min values

c_m = matplotlib.cm.cool

s_m = matplotlib.cm.ScalarMappable(cmap='jet', norm=norm)

s_m.set_array([])

#below is the for loop that uses one value of T at a time, represented as t in the equation

for t in pof6:            

    plt.plot(x, b*x/(((a*t*x**2/(m**2))+1)**2)*e, color=s_m.to_rgba(t)) 

func = lambda x,pos: "{:g}".format(x)

fmt = matplotlib.ticker.FuncFormatter(func)

c_bar=plt.colorbar(s_m, format=fmt, ticks=[0.01**6,0.02* 0.03**6, 0.04**6])

plt.legend()

plt.xlabel('y=E/T')

plt.ylabel('$f_{ν_s}$')

c_bar.set_label(r'T(K)')

plt.show()

我尝试应用网站上建议的一些解决方案，例如将自定义刻度标签均匀地分布在颜色条上，但尚未成功。

Answer 1

您使用的是线性范数，其中pof值彼此非常接近。使用LogNorm会有所帮助。刻度格式化程序可以调整以按其格式显示值**6。下面的代码稍微移动了四个函数，因为使用示例中的代码，所有绘图似乎都是一致的。至少当我使用类似m=2（m代码中未定义）的东西时。import numpy as npimport matplotlib.pyplot as pltfrom matplotlib import colors as mcolorsfrom matplotlib import ticker as mtickerT = [0.01, 0.02, 0.03, 0.04]  # values for the colourbar to use in equation in for loopx = np.linspace(0, 8, 100)e = 1 / (np.exp(x) + 1)  # factor used in equation dependent on the x-axis valuesa = 6.4 * 10 ** (-9)b = 1.51  # constants for the equationpof6 = [number ** 6 for number in T]norm = mcolors.LogNorm(vmin=np.min(pof6), vmax=np.max(pof6))  # colourbar max and min valuess_m = plt.cm.ScalarMappable(cmap='jet', norm=norm)s_m.set_array([])m = 2for t in pof6:    plt.plot(x, b * x / (((a * t * x ** 2 / (m ** 2)) + 1) ** 2) * e + 10*t**(1/6), color=s_m.to_rgba(t))func = lambda x, pos: "{:g}**6".format(x**(1/6) )fmt = mticker.FuncFormatter(func)c_bar = plt.colorbar(s_m, format=fmt, ticks=pof6)c_bar.set_label(r'T(K)')# plt.legend() # there are no labels set, so a default legend can't be createdplt.xlabel('y=E/T')plt.ylabel('$f_{ν_s}$')plt.show()如果您想要图例，则需要为每条曲线添加标签，例如：for t in pof6:    plt.plot(x, b * x / (((a * t * x ** 2 / (m ** 2)) + 1) ** 2) * e, color=s_m.to_rgba(t),             label=f'$t = {t**(1/6):g}^6$')plt.legend()