只是想知道将 letterSelected 传递到 useLazyQuery fetchMovies 查询中的最佳方法,这样我就不必使用“A”的静态变量。我希望有一种方法可以将它直接传递到 fetchMovies 中。useLazyQuery 是一个 apollo 查询。
const BrowseMovies = () => {
const [fetchMovies, { data, loading}] = useLazyQuery(BROWSE_MOVIES_BY_LETTER, {
variables: {
firstLetter: "A"
}
})
return (
<div className="browserWrapper">
<h2>Browse Movies</h2>
<AlphabetSelect
pushLetterToParent={fetchMovies}
/>
{
data && !loading &&
data.browseMovies.map((movie: any) => {
return (
<div className="browseRow">
<a className="movieTitle">
{movie.name}
</a>
</div>
)
})
}
</div>
)
}
export default BrowseMovies
const AlphabetSelect = ({pushLetterToParent}: any) => {
const letters = ['A','B','C','D','E','F','G','H','I','J','K','L', 'M','N','O','P','Q','R','S','T','U','V','W','X','Y','Z','#']
const [selectedLetter, setSelectedLetter] = useState("A")
const onLetterSelect = (letter: string) => {
setSelectedLetter(letter.toUpperCase())
pushLetterToParent(letter.toUpperCase())
}
return (
<div className="alphabetSelect">
{
letters.map((letter: string) => {
return(
<div
className={selectedLetter === letter ? 'letterSelectActive' : 'letterSelect'}
onClick={() => onLetterSelect(letter)}
>
{letter}
</div>
)
})
}
</div>
)
}
export default AlphabetSelect
慕的地10843
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