这是我的代码:
for i in matches:
driver.get(i)
Country = WebDriverWait(driver, 2).until(EC.visibility_of_element_located((By.XPATH, "/html/body/div[4]/div[5]/div/div/div[1]/section/ul/li[3]/a"))).text
leagueseason = WebDriverWait(driver, 2).until(EC.visibility_of_element_located((By.XPATH, "/html/body/div[4]/div[5]/div/div/div[1]/section/header/h1/a"))).text
Date = WebDriverWait(driver, 2).until(EC.visibility_of_element_located((By.ID, 'match-date'))).text
Date = Date.replace(".", "/").replace("-", "").replace(" ", "", 1)
Home = WebDriverWait(driver, 2).until(EC.visibility_of_element_located((By.XPATH, "/html/body/div[4]/div[5]/div/div/div[1]/section/ul[2]/li[1]/h2/a"))).text
Away = WebDriverWait(driver, 2).until(EC.visibility_of_element_located((By.XPATH, "/html/body/div[4]/div[5]/div/div/div[1]/section/ul[2]/li[3]/h2/a"))).text
ft = WebDriverWait(driver, 2).until(EC.visibility_of_element_located((By.ID, 'js-score'))).text
Res = ""
try:
extrainfo = driver.find_element_by_xpath("//*[@id='js-eventstage']").text
except NoSuchElementException:
extrainfo = " "
现在我会TimeoutException在页面未加载时添加一个,我尝试这样做:
try:
#previous code
except TimeoutException:
driver.get(i)
这样,当我遇到超时错误时,代码将跳过 url 抓取并继续处理下一个 url。我该如何解决这个问题?我希望在超时的情况下它会重新加载页面并再次抓取该网址的数据。
大话西游666
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