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万千封印
eacha是在下一次迭代中取下一个值的循环变量。将转换后的值存储在另一个列表中。a = ['3.465759','2.8797','9.23544']b = []for each in a: print(each) each = round(float(each),3) + 2 b.append(each)print(b)输出:3.4657592.87979.23544[5.466, 4.88, 11.235]或者如果你想就地修改列表,那么a = ['3.465759','2.8797','9.23544']for i in range(len(a)): each = a[i] print(each) each = round(float(each),3) + 2 a[i] = eachprint(a)或者使用列表理解[round(float(each),3) + 2 for each in a]
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九州编程
您可以使用地图:a = ['3.465759','2.8797','9.23544']
float_list = list(map(float, a))
print(float_list)输出:[3.465759, 2.8797, 9.23544]
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慕码人8056858
a = ['3.465759','2.8797','9.23544']result = []for each in a: each = round(float(each),3) + 2 result.append(each)print(result)Output: [5.466, 4.88, 11.235]这是你想要的?
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慕婉清6462132
你没有改变a,当你进行转换时,请确保更改值:即:a = ['3.465759','2.8797','9.23544']for i in range(len(a)): each = a[i] print(each) each = round(float(each),3) + 2 a[i] = each print(a)或者a = ['3.465759','2.8797','9.23544']for i, each in enumerate(a): print(each) each = round(float(each),3) + 2 a[i] = each print(a)3.4657592.87979.23544[5.466, 4.88, 11.235]