印刷星星图案

Question

我正在尝试打印如下所示的星形图案

*

**

***

****

*****

但我得到了这个。

*

**

***

****

*****

*****

最后一行 star 似乎有重复，我不知道为什么会这样。你能帮助我吗？

这是我的代码：

public class Test1 {

    public static void main(String[] args) {

        for (int i = 1; i <= 5; i++) {

            System.out.println("*");

            for (int j = 1; j <= i; j++) {

                System.out.print("*");

            }

        }

    }

}

Answer 1

你把换行符放在错误的位置。我会把它与写作分开*，比如public class Test1 {&nbsp; &nbsp; public static void main(String[] args) {&nbsp; &nbsp; &nbsp; &nbsp; for (int i = 1; i <= 5; i++) {&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; for (int j = 1; j <= i; j++) {&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; System.out.print("*");&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; }&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; System.out.println();&nbsp; &nbsp; &nbsp; &nbsp; }&nbsp; &nbsp; }}

Answer 2

*你一开始就打印一个。它应该像你正在做的那样完成。在 1 次完整迭代后打印新行For，如下所示：代码：for (int i = 1; i <= 5; i++)&nbsp;{&nbsp; &nbsp; //System.out.println("*");&nbsp; &nbsp;// This line should not be here&nbsp;&nbsp; &nbsp; for (int j = 1; j <= i; j++)&nbsp;&nbsp; &nbsp; {&nbsp; &nbsp; &nbsp; &nbsp; System.out.print("*");&nbsp; &nbsp; }&nbsp; &nbsp; System.out.println();&nbsp; &nbsp; &nbsp; &nbsp; // you can print new line after each nested-for compleletion}

Answer 3

简短回答（TL；DR）你的换行符放错了。在内部 for 循环执行之后放置换行符，如下所示：public class Test1 {public static void main(String[] args) {&nbsp; &nbsp; for (int i = 1; i <= 5; i++) {&nbsp; &nbsp; &nbsp; &nbsp; for (int j = 1; j <= i; j++) {&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; System.out.print("*");&nbsp; &nbsp; &nbsp; &nbsp; }&nbsp; &nbsp; &nbsp; &nbsp; System.out.println();&nbsp; &nbsp; }&nbsp; }}详细解答首先，您必须了解System.out.print()和之间的区别System.out.println()。这两个基本上做同样的事情：他们打印出传递给他们的参数。但是，有一个明显的区别：System.out.println()在打印后生成一个新的换行符，但System.out.print实际上并没有。要理解这个概念，请检查下面的示例代码：System.out.println("Tadaa");System.out.print("Ta");System.out.print("daa");System.out.print("Stackoverflow");其输出将是：多田多田堆栈溢出使用这个逻辑，很容易看出哪里出了问题。直觉上，中断 [ .println()] 应该发生在每次迭代结束时。我希望这有帮助。编码愉快！

Answer 4

这是所需输出的代码for (int i = 1; i <= 5; i++)&nbsp;{&nbsp; &nbsp; //System.out.println("*");&nbsp; &nbsp;&nbsp; &nbsp; for (int j = 1; j <= i; j++)&nbsp;&nbsp; &nbsp; {&nbsp; &nbsp; &nbsp; &nbsp; System.out.print("*");&nbsp; &nbsp; }&nbsp; &nbsp; System.out.println();&nbsp; &nbsp; &nbsp; &nbsp;&nbsp;}