如何使用方法初始化类中的字符串数组?
private static String[] strNrs2 =
{"Zero","One","Two","Three","Four","Five","Six","Seven","Eight","Nine"};
private static String[] colo = arr();
private String[] arr(){
String[] str99 = new String[strNrs2.length];
for (int i = 0; i<strNrs2.length;i++){
str99[i]= new StringBuilder(strNrs2[i]).reverse().toString();
}
return str99;
}
我要这个 :
private static String[] strNrs2 =
{"Zero","One","Two","Three","Four","Five","Six","Seven","Eight","Nine"};
看起来像这样:
private static String[] strNrs =
{"oreZ","enO","owT","eerhT","ruoF","eviF","xiS","neveS","thgiE","eniN"};
但我只想做一次。因为我计划循环使用该数组的方法数百万次。因此它会大大降低我的运行速度。
完整代码:
public class IntToStr {
private static String[] strNrs2 = {"Zero","One","Two","Three","Four","Five","Six",
"Seven","Eight","Nine"};
public static String intToStr(int nr) {
StringBuilder str = new StringBuilder("");
while (nr>0) {
int pop = nr%10;
nr= nr/10;
str.append(new StringBuilder(strNrs2[pop]).reverse().toString());
//By using this str.append(strNrs[pop]); runtime will increase considerably.
}
return str.reverse().toString();
}
public static void main(String[] args) {
for (int i = 0; i<10000000;i++)
intToStr(5555555);
System.out.println("Finished");
}
}
MMMHUHU
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