如何同时打印和扫描

Question

我正在编写一个简单的贪吃蛇游戏。

这将是非常基本的，但我现在被困住了。我使用“wsad”来引导蛇，但在原始游戏中，即使我们没有改变它的方向，蛇也会移动。我的代码等待我输入一个字母，然后蛇就会移动。所以这是我测试如何弄清楚的示例，但我无法得到结果。

package main

import (

    "fmt"

    "github.com/eiannone/keyboard"

    "time"

)

func takeLetter(s chan bool) {

    char, _, err := keyboard.GetSingleKey()

    if err != nil {

        panic(err)

    }

    fmt.Printf("%c", char)

    s <- true

}

func Print(c chan bool) {

    fmt.Println("snake is moving")

    time.Sleep(1 * time.Second)

    c <- true

}

func main() {

    c := make(chan bool)

    s := make(chan bool)

    for {

        go takeLetter(s)

        go Print(c)

        <-s

        <-c

    }

}

即使我们没有按下任何键，我如何管理此代码以打印“snake is moving”？

Answer 1

您的代码明确同步它们：for {&nbsp; &nbsp; go takeLetter(s)&nbsp; &nbsp; go Print(c)&nbsp; &nbsp; <-s&nbsp; &nbsp; <-c}该循环的每次迭代，每个函数都将执行一次，并且它将等待再次执行循环，直到两者都完成（这就是您对通道所做的）。您可能想要的是对每个函数运行一次，并让每个循环独立运行：func takeLetter() {&nbsp; &nbsp; for {&nbsp; &nbsp; &nbsp; &nbsp; char, _, err := keyboard.GetSingleKey()&nbsp; &nbsp; &nbsp; &nbsp; if err != nil {&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; panic(err)&nbsp; &nbsp; &nbsp; &nbsp; }&nbsp; &nbsp; &nbsp; &nbsp; fmt.Printf("%c", char)&nbsp; &nbsp; }}func Print() {&nbsp; &nbsp; for {&nbsp; &nbsp; &nbsp; &nbsp; fmt.Println("snake is moving")&nbsp; &nbsp; &nbsp; &nbsp; time.Sleep(1 * time.Second)&nbsp; &nbsp; }}func main() {&nbsp; &nbsp; &nbsp; &nbsp; go takeLetter()&nbsp; &nbsp; &nbsp; &nbsp; go Print()&nbsp; &nbsp; &nbsp; &nbsp; select {} // keep main from exiting immediately}