索引.jsx
import React from "react";
import ReactDOM from "react-dom";
import { Route, Router, Switch } from "react-router-dom";
import App from "./components/App.jsx";
import SearchResults from "./components/SearchResults.jsx";
import history from "./history.js";
import SearchProvider from "./context/SearchContext.jsx";
const routing = (
<Router history={history}>
<div>
<Switch>
<SearchProvider>
<Route path="/search" component={SearchResults} />
<Route exact path="/" component={App} />
</SearchProvider>
</Switch>
</div>
</Router>
);
ReactDOM.render(routing, document.getElementById("app"));
应用程序.jsx
import React, { useState } from "react";
import styles from "../modules/app.module.css";
import Search from "./Search.jsx";
import { Link } from "react-router-dom";
const App = (props) => {
return (
<div className={styles.appContainer}>
<div className={styles.title}>BGrules</div>
<Search />
<Link to="/search">
<button>Click me</button>
</Link>
</div>
);
};
export default App;
搜索结果.jsx
import React from "react";
import styles from "../modules/searchResults.module.css";
const SearchResults = (props) => {
return (
<div className={styles.resultContainer}>
<div className={styles.title}>Search Results</div>
<div className={styles.subTitle}>results for term:</div>
</div>
);
};
export default SearchResults;
我遇到的问题是,当我在 url 中键入路由 /search 时,它会毫无问题地将我带到正确的页面,但是当我尝试在我的 App 文件中使用 Link 或 Redirect 时,它会更改 url 但不会加载该组件(只是一个空白的白页)我在控制台中没有收到任何错误。我不熟悉在这里提问,所以希望我以一种有意义的方式提问。提前致谢!
智慧大石
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