我有一个tsv如下所示的文件
Time Object pmPdDrb pmPdcDlSrb
00:45 EUtranCellFDD=GNL02294_7A_1 2588007 1626
00:45 EUtranCellFDD=GNL02294_7B_1 18550 32
00:45 EUtranCellFDD=GNL02294_7C_1 26199 38
00:45 EUtranCellFDD=GNL02294_9A_1 3857243 751
是否可以像下面这样将其转换为 XML?
<xmlnode>
<Time>00:45</Time>
<Object>EUtranCellFDD=GNL02294_7A_1</Object>
<pmPdDrb>2588007</pmPdDrb>
<pmPdcDlSrb>1626</pmPdcDlSrb>
</xmlnode>
我试过下面的代码:
var reader = File.ReadAllLines(logFile);
var xml1 = new XElement("TopElement",
reader.Select(line => new XElement("Item",
line.Split('\t').Select((column, index) =>
new XElement("Column" + index,column)))
)
);
偶然的你
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