我已经成功地做了一个同步解决方案,没有对调用的干扰。findMaxcompute
package main
import (
"context"
"fmt"
"math/rand"
"time"
)
func findMax(ctx context.Context, concurrency int) uint64 {
var (
max uint64 = 0
num uint64 = 0
)
for i := 0; i < concurrency; i++ {
num = compute()
if num > max {
max = num
}
}
return max
}
func compute() uint64 {
// NOTE: This is a MOCK implementation of the blocking operation.
time.Sleep(time.Duration(rand.Int63n(100)) * time.Millisecond)
return rand.Uint64()
}
func main() {
maxDuration := 2 * time.Second
concurrency := 10
ctx, cancel := context.WithTimeout(context.Background(), maxDuration)
defer cancel()
max := findMax(ctx, concurrency)
fmt.Println(max)
}
https://play.golang.org/p/lYXRNTDtNCI
当我尝试使用 goroutines 来重复调用函数时使用尽可能多的 goroutines,直到上下文被调用方函数取消。我每次都得到0,而不是灌浆计算函数调用的预期最大值。我尝试了不同的方法来做到这一点,并且大部分时间都陷入僵局。findMaxcomputectxmain
package main
import (
"context"
"fmt"
"math/rand"
"time"
)
func findMax(ctx context.Context, concurrency int) uint64 {
var (
max uint64 = 0
num uint64 = 0
)
for i := 0; i < concurrency; i++ {
select {
case <- ctx.Done():
return max
default:
go func() {
num = compute()
if num > max {
max = num
}
}()
}
}
return max
}
func compute() uint64 {
// NOTE: This is a MOCK implementation of the blocking operation.
time.Sleep(time.Duration(rand.Int63n(100)) * time.Millisecond)
return rand.Uint64()
}
func main() {
maxDuration := 2 * time.Second
concurrency := 10
ctx, cancel := context.WithTimeout(context.Background(), maxDuration)
defer cancel()
max := findMax(ctx, concurrency)
fmt.Println(max)
}
https://play.golang.org/p/3fFFq2xlXAE
元芳怎么了
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