PHP 中的变量在 ajax 请求后丢失

Question

我的目标 - 通过条纹或PayPal付款，一旦完成，向客户出示一份表格，上传文件以通过电子邮件发送给我。我的表单处于自举模态中。我正在尝试确保除非付款，否则无法提交表单。

客户当前付款，由 ajax 完成。这工作正常，并显示付款ID。但是，当我向同一 php 文档发送另一个 ajax 请求时，要完成电子邮件发送，使用 ，该变量已丢失其值。$send_form = $_POST["email_form"];$payment_made

<?php

$send_form = $_POST["email_form"]; //this is sent by ajax. Will be 'yes' if the form to send has been submitted.

switch ($action){

  case 'stripe':

    //do stripe transaction

    //set a variable to indicate payment is complete using transaction ID

    $payment_made = $transaction->id;

  break;

  case 'paypal':

    //do paypal transaction

    //set a variable to indicate payment is complete using transaction ID

    $payment_made = $transaction->id;

  break;

}

function sendmail() {

  //usual php mail function (works fine)

}

if ($send_form = 'yes' && $payment_made != '') {

  sendmail();

}

?>

我的问题：如何使用变量来验证付款是否已完成，以防止未经授权使用电子邮件表单？$payment_made

除非有要求，否则我不会上传ajax或html代码，因为它都可以正常工作，只要我在使用之前不检查变量。$payment_madephpmail()

Answer 1

我使用PHP会话来存储然后删除变量。<?phpsession_start();$send_form = $_POST["email_form"]; //this is sent by ajax. Will be 'yes' if the form to send has been submitted.switch ($action){&nbsp; case 'stripe':&nbsp; &nbsp; //do stripe transaction&nbsp; &nbsp; //set a variable to indicate payment is complete using transaction ID&nbsp; &nbsp; $_SESSION["payment_made"] = $transaction->id;&nbsp; break;&nbsp; case 'paypal':&nbsp; &nbsp; //do paypal transaction&nbsp; &nbsp; //set a variable to indicate payment is complete using transaction ID&nbsp; &nbsp; $_SESSION["payment_made"] = $transaction->id;&nbsp; break;}function sendmail() {&nbsp; //usual php mail function (works fine)&nbsp; session_unset();&nbsp; session_destroy();&nbsp; mail();}if ($send_form = 'yes' && $_SESSION["payment_made"] != '') {&nbsp; sendmail();&nbsp;}?>