查找字符之间的句子

Question

我正在尝试在 pipe|和 dot之间找到句子.，例如

| 这是一。这是两个。

我使用的正则表达式模式：

preg_match_all('/(:\s|\|+)(.*?)(\.|!|\?)/s', $file0, $matches);

到目前为止，我无法捕捉到这两个句子。我使用的正则表达式仅捕获第一句话。

我怎么解决这个问题？

编辑：从正则表达式中可以看出，我试图找到句子 BETWEEN (: or |) AND (. or ! or ?)

列或管道表示句子的起点。句子可能是：

: Sentence one. Sentence two. Sentence three. 

| Sentence one. Sentence two? 

| Sentence one. Sentence two! Sentence three?

Answer 1

另一种选择是利用\G迭代匹配来断言前一个匹配结束时的位置，并捕获捕获组中匹配点和 0+ 水平空白字符之后的值。(?:\|\h*|\G(?!^))([^.\r\n]+)\.\h*在零件(?:非捕获组\|\h*匹配|和 0+ 个水平空白字符|或者\G(?!^)在上一场比赛结束时断言位置)关闭组(捕获组 1 匹配除换行符- [^.\r\n]+以外的任何字符 1 次以上.)关闭组\.\h*匹配 1 个.和 0+ 个水平空白字符例如$re = '/(?:\|\h*|\G(?!^))([^.\r\n]+)\.\h*/';$str = '| This is one. This is two.John loves Mary.| This is one. This is two.';preg_match_all($re, $str, $matches, PREG_SET_ORDER, 0);print_r($matches);输出Array(    [0] => Array        (            [0] => | This is one.             [1] => This is one        )    [1] => Array        (            [0] => This is two            [1] => This is tw        ))

Answer 2

这可以完成工作：$str = '| This is one. This is two.';preg_match_all('/(?:\s|\|)+(.*?)(?=[.!?])/', $str, $m);print_r($m)输出：Array(    [0] => Array        (            [0] => | This is one            [1] =>  This is two        )    [1] => Array        (            [0] => This is one            [1] => This is two        ))

Answer 3

我会保持简单，只需匹配：\s*[^.|]+\s*这表示匹配任何不包含管道或句号的内容，并且它还会在每个句子之前/之后修剪可选的空格。$input = "| This is one. This is two.";preg_match_all('/\s*[^.|]+\s*/s', $input, $matches);print_r($matches[0]);这打印：Array(    [0] =>  This is one    [1] =>  This is two)